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Answer:
it is not express because the line is parallel at y axis
Step-by-step explanation:
As ray UW bisects ( divides the angles into two equal parts )
WUT = WUV
6x - 10° = 4x + 6°
6x - 4x = 6° + 10°
2x = 16°
x = 16° ÷ 2 = 8°
Putting the value of x in the Angle WUT
6 × 8° - 10° = 48° - 10° = 38°
This is a great question, but it's also a very broad one. Please find and post one or two actual rational expressions, so we can get started on specifics of how to find vertical and horiz. asymptotes.
In the case of vert. asy.: Set the denom. = to 0 and solve for x. Any real x values that result indicate the location(s) of vertical asymptotes.
H=-16t² +v(0)t+h(0)
v(0)=192
h=-16t² +192t+h(0)
h(0) should be 0, because the mortar sits on the ground.
h= - 16t²+192t
This function will have maximum because it has minus before x², and parabola is looking down.
h=-(16t²-192t)=-(16t² -2*4t*24+24²)+24²
h=-(4t-24)²+24²
h=-(4t-24)²+576
vertex (24 feet, 576 feet)
24 feet horizontally from the mortar and 576 feet up
