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Degger [83]
3 years ago
14

If someone makes $1000 every second, how much will they have in an hour?

Mathematics
1 answer:
Vinvika [58]3 years ago
5 0

Answer:

reference to gta money glitch?

Step-by-step explanation:

idk

600,000k

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The length of a rectangular is 7/10 ft .and the width is 1/5ft what is the perimeter
Blababa [14]
<h3>Answer:</h3>

\huge\boxed{1 \frac{4}{5}\ \text{ft}}

<h3>Explanation:</h3>

Change \frac{1}{5} so that is has a common denominator.  \frac{1*2}{5*2}=\frac{2}{10}

Make an equation.  \frac{7+7+2+2}{10}

Add.  \frac{14+4}{10}

Add.  \frac{18}{10}

Divide both sides by 2.  \frac{9}{5}

Convert to a mixed number.  1 \frac{4}{5}

4 0
3 years ago
Read 2 more answers
I am stuck on how to do 10 percent of $55.86
faust18 [17]

Answer:

read step by step

Step-by-step explanation:

.10×55.86 = 5.58

then subtract $5.58 from your total .

and that will give you the answer

8 0
3 years ago
What is the equation of the quadratic graph with a focus of (3, 6) and a directrix of y = 4? f(x) = one fourth (x − 3)2 + 1 f(x)
mina [271]
 Let point (x, y) be any point on the graph, than the distance between (x, y) and the focus (3, 6) is sqrt((x - 3)^2 + (y - 6)^2) and the distance between (x, y) and the directrix, y = 4 is |y - 4|

Thus sqrt((x - 3)^2 + (y - 6)^2) = |y - 4|
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
x^2 - 6x + 9 + y^2 - 12y + 36 = y^2 - 8y + 16
x^2 - 6x + 29 = -8y + 12y = 4y
(x - 3)^2 + 20 = 4y
y = 1/4(x - 3)^2 + 5

Required answer is f(x) = one fourth (x - 3)^2 + 5
8 0
3 years ago
A loaf of bread costs $1.40 and the markup is 30% of the selling price. Find the selling price.
andreev551 [17]

Answer:

The selling price after the markup is $1.82

Step-by-step explanation:

$1.40 * .30 =

Multiply $1.40 times .30 (which is same as 30%)

$1.40 * .30 = $0.42

Add $1.40 and $0.42

= $1.82

Hope this helps.

6 0
3 years ago
Radioactive Decay Beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining
Flura [38]

Answer:

the equation should be corrected to fit the data of the problem.  With the corrected equation a mass of 0.5 grams remains after 150 years

Step-by-step explanation:

for the mass y( in grams)

y=23* (1/2)^(t/45), t ≥ 0.

the initial mass is at t=0 , then

y= 23 grams  → should be 16 grams

half-life from the equation = 45 years → should be 30 years

the correct equation should be

y=16*(1/2)^(t/30), t ≥ 0

then after 150 years  → t= 150

y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams

then a mass of 0.5 grams remains after 150 years

5 0
3 years ago
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