If a car travels 80 km/total distance is 450 km, how much time is required to reach? A car covers half of the distance between two places at 40km per hour and the other half distance at 60 km per hour!
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Responder:
24 litros; 16 litros; 4 litros
Explicación paso a paso:
Dado que:
Gasolina consumida = 20 litros
Sea la cantidad de gasolina en el tanque = x
Primera parte del viaje = 2/3 de x
Segunda parte del viaje = 1/2 de (x - 2x / 3)
Cantidad de gasolina en el tanque:
2x / 3 + 1/2 (x - 2x / 3) = 20
Solución para x
2x / 3 + x / 2 - x / 3 = 20
(4x + 3x - 2x) / 6 = 20
5 veces / 6 = 20
5 veces = 20 * 6
5 veces = 120
x = 120/5
x = 24
Cantidad de gasolina en el tanque = 24 litros
Litros consumidos en cada etapa:
Primera parte = 2/3 de 24 = 48/3 = 16 litros
2a parte = 0.5 de (24 - 16) = 0.5 * 8 = 4 litros
Answer:
x= 81°, z= 99°, y°=68°
Step-by-step explanation:
considering the part of the triangle where 36° , 63° and x° is located as ΔABC.
to find the measure of x we use angle sum property.
We know that the sum of the angles of a triangle is always 180°. Therefore, if we know the two angles of a triangle, and we need to find its third angle, we use the angle sum property. We add the two known angles and subtract their sum from 180° to get the measure of the third angle.
so,
∠A + ∠B +∠C = 180°
36° + 63° + x° = 180°
99° + x° = 180°
x° = 180 - 99
x° = 81°
When two lines intersect each other at a single point, linear pairs of angles are formed. If the angles so formed are adjacent to each other after the intersection of the two lines, the angles are said to be linear. If two angles form a linear pair, the angles are supplementary, whose measures add up to 180°.
x° + z° = 180°
81° + z = 180°
z= 180 - 81
z= 99°
considering the next part of the triangle where 13° , z° and y° is located as ΔACD
to find the measure of y we use angle sum property.
∠A + ∠C + ∠D = 180°
13° + z° + y° = 180°
13°+99°+y°= 180°
112°+ y° = 180°
y°= 180- 112
y° = 68°
A=8
B=10
Hope this helps :D
Answer:
see explanation
Step-by-step explanation:
∠ PQX = 90° ( angle in a semicircle )
∠ PXQ = 42° ( alternate angle theorem )
Angle between tangent and diameter is right, thus
∠ XPQ = 90° - 42° = 48°
