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wlad13 [49]
3 years ago
15

Solve any method: 9x^2+9x=4??

Mathematics
2 answers:
Gala2k [10]3 years ago
6 0
Subtract 4 from both sides, solve using quadratic formula
ax^2+bx+c
(-b(+or-) Square Root of b^2 - 4ac)/2a

9x^2+9x-4=0
-9(+or-)Square root of 9^2-4(9)(-4)/2(9)

Solve^
svetoff [14.1K]3 years ago
4 0
9x² + 9x = 4
9x² + 9x - 4 = 4 - 4
9x² + 9x - 4 = 0
x = <u>-9 +/- √(9² - 4(9)(-4))</u>
                2(9)
x = <u>-9 +/- √(81 + 144)</u>
                 18
x = <u>-9 +/- √225
</u>            18
x = <u>-9 +/- 15</u>
           18
x = <u>-9 + 15</u>    x = <u>-9 - 15</u>
          18                 18
x = <u>6</u>             x = <u>-24</u>
     18                    18
x = 1/3            x = -1 1/3
         
<u />
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The length of each square on the grid represents 1 cm. The scale
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Step-by-step explanation:

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5 0
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-6/7,-3/7,0,3/7 .... create a formula that explains the arithmetic sequence
LenKa [72]

The formula that explain the arithmetic sequence is a_{n}=\frac{3}{7}n-\frac{9}{7}

Step-by-step explanation:

The formula of the nth term in an arithmetic sequence is

a_{n}=a+(n-1)d , where

  • a is the first term
  • d is the common difference between the consecutive terms

∵ \frac{-6}{7} , \frac{-3}{7} , 0 , \frac{3}{7} are some terms of an arithmetic sequence

∵ The difference between two consecutive terms = \frac{-3}{7} - \frac{-6}{7}

∴ The difference between two consecutive terms = \frac{-3}{7} + \frac{6}{7} = \frac{3}{7}

∴ The common difference = \frac{3}{7}

∴ d = \frac{3}{7}

∵ The first term is \frac{-6}{7}

∴ a = \frac{-6}{7}

- Substitute a and d in the formula above

∴ a_{n}=\frac{-6}{7}+(n-1)\frac{3}{7}

- Simplify the right hand side

∴ a_{n}=\frac{-6}{7}+\frac{3}{7}n-\frac{3}{7}

- Add like terms

∴ a_{n}=\frac{3}{7}n-\frac{9}{7}

The formula that explain the arithmetic sequence is a_{n}=\frac{3}{7}n-\frac{9}{7}

Learn more:

You can learn more about the sequences in brainly.com/question/7221312

#LearnwithBrainly

3 0
3 years ago
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