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Whitepunk [10]
3 years ago
11

A prism has an volume of 8 yd3. What is its volume in ft3?

Mathematics
2 answers:
andrey2020 [161]3 years ago
7 0

Answer:

24ft^3

Step-by-step explanation:

Since there are 3 feet in a yard, times 8 by 3 to get your answer!

8 x 3= 24 so 24ft^3

Kaylis [27]3 years ago
3 0
8x3=24 ft3 3 feet are in a yard.
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A property of triangles<span> that states that if the side lengths of a </span>triangle<span> are fixed, the </span>triangle can have only one shape.The triangle is the strongest shape due to the rigidity of its sides, which allows them to transfer force more evenly through their sides than other shapes.<span> Triangles are used extensively in the construction of buildings and bridges.</span><span> triangle cannot be deformed without changing its joints</span>
7 0
3 years ago
Andrew is paid $4 per hour for the first 30 hours he works each week. He makes $5 per hour for each hour he works over 30 hours
klasskru [66]

Answer:

If Andrew works for 30 for $4 he will have a total wage of 30×4=$120

And gets additional $5for every hr worked beyond 30hrs in that week

So he gets a total of 5(x-30)

So if he works for 40hrs he gets a total wage of

5(40-30)=50

120+50=$170

If he works for 50 hours he gets Total wage of

5(50-30)=100

120+100=$220

4 0
4 years ago
How do I do this, I really need some help
meriva
You solve for x and get x<-2 or x>= -1/2 and then graph

4 0
3 years ago
A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum
Ivan

Answer:

Differential equation

\frac{dy}{dt} =ky(1-y)

Solution

y=\frac{1}{1+4e^{-0.327t}}

Value of constant k=0.327 days^(-1)

The rumor reaches 80% at 8.48 days.

Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

\frac{dy}{dt} =ky(1-y)

Solving the differential equation

\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}

Initial conditions:

y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48

The rumor reaches 80% at 8.48 days.

8 0
3 years ago
(3cosx-4sinx) + (3sinx+4cosx) = 5
Ksenya-84 [330]
(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0

Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º      (360º-53.13º=306.87)

sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º

The solutions when  0≤x≤360º are:  36.87º and 306.87º.


3 0
3 years ago
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