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miss Akunina [59]
3 years ago
13

Please solve due soon

Mathematics
2 answers:
andrezito [222]3 years ago
6 0

Answer:

5

Step-by-step explanation:

5+5(0)

melisa1 [442]3 years ago
4 0
The correct answer would be 5 because if x=0 then 5 0 times would just be zero
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Kristen is jogging in a straight line. She got a head start of 7 meters from the starting line, and she ran 2 meters every 9 sec
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6 0
3 years ago
Each of 7 students reported the number of movies they saw in the past year. This is what they reported.
Lady_Fox [76]

Answer:

A is 6

B is 9.4

Step-by-step explanation:

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6 0
2 years ago
I need to know how to do the whole thing and understand it.
patriot [66]

We are given the data on the number of candies handed by neighborhood A and neighborhood B.

Let us first find the mean and variance of each neighborhood.

Mean:

\bar{x}_A=\frac{\sum x}{N_1}=\frac{12}{6}=2\bar{x}_B=\frac{\sum x}{N_2}=\frac{20}{6}=3.33

Variance:

s_A^2=\frac{\sum x^2}{N_1}-\bar{x}_A^2=\frac{28}{6}-2^2=0.667s_B^2=\frac{\sum x^2}{N_2}-\bar{x}_B^2=\frac{80}{6}-3.33^2=2.244

A. Null hypothesis:

The null hypothesis is that there is no difference in the mean number of candies handed out by neighborhoods A and B.

H_0:\;\mu_A=\mu_B

Research hypothesis:

The research hypothesis is that the mean number of candies handed out by neighborhood A is more than neighborhood B.

H_a:\;\mu_A>\mu_B

Test statistic (t):

The test statistic of a two-sample t-test is given by

t=\frac{\bar{x}_A-\bar{x}_B}{s_p}

Where sp is the pooled standard deviation given by

\begin{gathered} s_p=\sqrt{\frac{N_1s_1^2+N_2s_2^2}{N_1+N_2-2}(\frac{N_1+N_2}{N_1\cdot N_2}}) \\ s_p=\sqrt{\frac{6\cdot0.667+6\cdot2.244}{6+6-2}(\frac{6+6}{6\cdot6})} \\ s_p=0.763 \end{gathered}t=\frac{2-3.33}{0.763}=-1.74

So, the test statistic is -1.74

Critical t:

Degree of freedom = N1 + N2 - 2 = 6+6-2 = 10

Level of significance = 0.05

The right-tailed critical value for α = 0.05 and df = 10 is found to be 1.81

Critical t = 1.81

We will reject the null hypothesis because the calculated t-value is less than the critical value.

Interpretation:

This means that we do not have enough evidence to conclude that neighborhood A gives out more candies than neighborhood B.

6 0
1 year ago
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