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4 years ago

What is 34696 rounded to 2 significant figures

1 answer:

4 0

The answer is 35000. Because 2 significant figures means the 2nd number, in this case it is the number 4 and if we want to round off something, look at the next number, if more than 5 or 5, you must round up.

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When 4(0.5x+2.5y-0.7-1.3y+4) is simplified, what is the resulting expression?

snow_lady [41]

Answer:

2x + 4.8y +13.2

Step-by-step explanation:

1. (4)(0.5x+2.5y+−0.7+−1.3y+4)

2. (4)(0.5x)+(4)(2.5y)+(4)(−0.7)+(4)(−1.3y)+(4)(4)

3. 2x+10y−2.8−5.2y+16

4. 2x + 4.8y +13.2

I hope this helped, please mark Brainliest, thank you!!

7 0

3 years ago

HELP!!! WILL GIVE 20 POINTS AND BRAINLIEST!!!!

777dan777 [17]

The answer is easily 12

6 0

3 years ago

I Have Some Questions For You Guys, A construction crew cut down thousands of acres of forest to build apartment buildings. How

Novosadov [1.4K]

Answer:

A. The population of deer will have to find a new habitat so they will have food to eat.

Step-by-step explanation:

Definitely not the others if you need explanation ask :)

3 0

3 years ago

Please help with this. I only need help with the first question I have the second one figured out,

lutik1710 [3]

Answer:

m∠WZX = 41°

Step-by-step explanation:

diagonals bisect angles and opposite angles are congruent

therefore, ∠WXY ≅ ∠WZY

∠WZY must equal [360 - 2(68)] ÷ 2 which equals 112°

If ∠WXZ = 71° then so does ∠XZY

Which means that ∠WZX must equal 112-71 which is 41°

6 0

3 years ago

Read 2 more answers

The Capulet and Montague families love writing. Last year, each Capulet wrote 44 essays, each Montague wrote 66 essays, and both

makvit [3.9K]

Answer: The answer is 2275 and 0.

Step-by-step explanation: Given that the Capulet and Montague families love to write. Last year, each Capulet wrote 44 essays, each Montague wrote 66 essays and both families wrote 100100 essays in total. This year, each Capulet wrote 88 essays, each Montague wrote 1212 essays, and both families wrote 200200 essays in total. We are to find the number of Capulets members and Montagues members.

Let there are 'x' members in Capulet family and 'y' members in the Montague family. Then, we have

$44x+66y=100100,\\\\88x+1212y=200200.$

Multiplying first equation by 2 and then subtracting from the second equation, we have

$1212y-132y=200200-200200\\\\\Rightarrow 1080y=0\\\\\Rightarrow y=0.$

So,

$x=\dfrac{100100}{44}=2275.$

Thus, there are 2275 Capulets and 0 Montagues.

7 0

3 years ago