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Paha777 [63]
3 years ago
7

What is 34696 rounded to 2 significant figures

Mathematics
1 answer:
Natali [406]3 years ago
4 0
The answer is 35000. Because 2 significant figures means the 2nd number, in this case it is the number 4 and if we want to round off something, look at the next number, if more than 5 or 5, you must round up.
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2(h-8) -h=h-16<br>A. 8<br>B. -8<br>C. No solution<br>D. Infinitely many solutions​
Grace [21]

Answer:

  D. Infinitely many solutions​

Step-by-step explanation:

The equation simplifies to ...

  2h -16 -h = h -16

  h -16 = h -16 . . . . . . a "tautology", true for all values of h.

There are infinitely many solutions.

7 0
3 years ago
Keira , larry and gita picked apples at an orchard. keira picked twice as many pounds as larry and 3 times as many as gita. the
Natalija [7]
Number of apples in pounds picked up by Keira = K
Number of apples in pounds picked up by Larry = L
Number of apples in pounds picked up by Gita = G
Total number of apples they picked all together in pounds = 8360
Now from the given question, we know
Number of apples picked up by Kiera = 2L
So
K = 2L
L = K/2
Again Kiera picked up 3 times as many apples as Gita picked.
So,
K = 3G
G = K/3
Now if we add all the apples in pounds picked up by the three of them.
Then
K + L + G = 8360
K + (K/2) + K/3) = 8360
(6K + 3K + 2K)/6 = 8360
11K/6 = 8360
11K = 8360 * 6
11K = 50160
K = 4560
Then
L = K/2
   = 4560/2
   = 2280
G = K/3
   = 4560/3
   = 1520
Now we can say that
Kiera picked 4560 pounds of apple
Larry picked 2280 pounds of apple
Gita picked 1520 pounds of apple
7 0
3 years ago
Find the volume of the solid generated when R​ (shaded region) is revolved about the given line. x=6−3sec y​, x=6​, y= π 3​, and
Dmitrij [34]

Answer:

V=9\pi\sqrt{3}

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

V=\int\limits^b_a {\pi r^{2}} \, dy

where:

r=6-(6-3 sec(y))

r=3 sec(y)

a=0

b=\frac{\pi}{3}

so the volume becomes:

V=\int\limits^\frac{\pi}{3}_0 {\pi (3 sec(y))^{2}} \, dy

This can be simplified to:

V=\int\limits^\frac{\pi}{3}_0 {9\pi sec^{2}(y)} \, dy

and the integral can be rewritten like this:

V=9\pi\int\limits^\frac{\pi}{3}_0 {sec^{2}(y)} \, dy

which is a standard integral so we solve it to:

V=9\pi[tan y]\limits^\frac{\pi}{3}_0

so we get:

V=9\pi[tan \frac{\pi}{3} - tan 0]

which yields:

V=9\pi\sqrt{3}]

6 0
3 years ago
How many square metre of carpeting are needed to cover a floor that measures 8m by 5m​
grigory [225]

Answer:

40 meters squared

Step-by-step explanation:

8 * 5 = 40

5 0
3 years ago
What’s a other word for adjacent I need help
Triss [41]

Answer: adjoining HAVE A GREAT DAY

8 0
2 years ago
Read 2 more answers
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