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fgiga [73]
3 years ago
15

If a point is equidistant from the endpoints of a segment then so

Mathematics
1 answer:
Karolina [17]3 years ago
6 0

Answer: If a point is equidistant from the endpoints of a segment, then the point is on the perpendicular bisector of the segment.

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Susan earned $75 for watching her neighbor's dog for 5 days. How much did Susan make in one day
Damm [24]
You need to find how many times 5 fits into 75 5x12=60 5x13=65 5x14=70 5x15=75. so, 5 fits in to 75 fifteen times. that means Susan makes $15 a day for 5 days. 5x15=75
6 0
3 years ago
Read 2 more answers
#7:Write the expression in simplest<br> radical form.<br> V24x5y2
vazorg [7]

2x^2y√6x


the image has the answer in a mor clear form


8 0
2 years ago
Find one of the solutions to the following absolute value equation:<br> 26 + 4) = 48
Sindrei [870]
Answer : MAYBE 18 (?)
I’m not 100% sure
Explanation: you always solve what’s is parentheses “( )” first so then you get the equation
30 = 48
Then ( this is the part I’m not sure about)
You subtract 30 out that means 30-30=0 & 48-30 = 18 so that’s where I found my answer but idk I haven’t done absolute value since Algebra 1 !!
7 0
3 years ago
14x+10y=72 14x+4y=96 Solve the following system of equations using any method
Anarel [89]
    14x + 10y = 72
    14x +   4y = 96
                6y = -24
                 6       6
                  y = -4
    14x + 10y = 72
14x + 10(-4) = 72
       14x - 40 = 72
             + 40 + 40
              14x = 112
               14      14
                  x = 8
            (x, y) = (8, -4)
5 0
3 years ago
Use integration by parts to find the integrals in Exercise.<br> ∫(4x-12)e-8x dx.
stepladder [879]

Answer:

e(2x^{2} -12x)-4x^{2}+C

Step-by-step explanation:

We have been given an indefinite integral as \int \left(4x-12\right)e-8x\:dx. We are asked to find the given integral.

Let us solve our given problem.

\int \left(4x-12\right)e\:dx-\int 8x\:dx

Take out constant:

e\int \left(4x-12\right)\:dx-8\int x\:dx

e(\int 4x\:dx -\int 12\right\:dx)-8\int x\:dx

e(\frac{4x^{1+1}}{2} -12x)-8*\frac{x^{1+1}}{1+1}+C

e(\frac{4x^{2}}{2} -12x)-8*\frac{x^{2}}{2}+C

e(2x^{2} -12x)-4x^{2}+C

Therefore, our required integral would be e(2x^{2} -12x)-4x^{2}+C.

5 0
3 years ago
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