We are given that Money magazine reported that a visit to a hospital emergency room for something as simple as a sore throat has a mean cost of $348 with a standard deviation of $87.

Let X = cost of a hospital emergency room visit for this medical service

So, X ~ N( $\mu=348, \sigma^{2} =87^{2}$ )

The standard normal z score distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

(a) Probability that the cost will be less than $500 = P(X < $500)

P(X < 500) = P( $\frac{X-\mu}{\sigma}$ < $\frac{500-348}{87}$ ) = P(Z < 1.75) = 0.95994 {from z table}

Therefore, the probability that the cost will be less than $500 is 0.95994 .

3 0

2 years ago

How to write a real world problem that could be solved using proportions

Debora [2.8K]

U can use real world numbers and problems to help

4 0

3 years ago

Read 2 more answers

Factor Completely'''

vekshin1

Answer:

$4x^2(x-2)(x+6)$

Step-by-step explanation:

Factor $4x^2$

$4x^2(x^2)+4x^2(4x)-4x^2(-12)$

$4x^2(x^2+4x-12)$

$4x^2(x-2)(x+6)$

<em>good luck, hope this helps :)</em>

5 0

2 years ago