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ella [17]
3 years ago
14

Determine the value of g(4), g(3 / 2), g (2c) and g(c+3) then simplify as much as possible.

Mathematics
2 answers:
jeka943 years ago
8 0

Answer:

g(4) = 8 \pi h\\\\g(\frac{3}{2}) = 3 \pi h\\\\ g(2c) = 4 \pi ch\\\\g(c+3) = 2 \pi hc+6\pi h

Step-by-step explanation:

You need to substitute r=4 into g(r) = 2 \pi r h. Then:

g(4) = 2 \pi(4)h\\\\g(4) = 8 \pi h

Substitute r=\frac{3}{2} into g(r) = 2 \pi r h. Then:

g(\frac{3}{2}) = 2 \pi(\frac{3}{2})h\\\\g(\frac{3}{2}) = 3 \pi h

Substitute r=2c into g(r) = 2 \pi r h. Then:

g(2c) = 2 \pi(2c))h\\\\g(2c) = 4 \pi ch

Substitute r=c+3 into g(r) = 2 \pi r h. Then:

g(c+3) = 2 \pi (c+3)h\\\\g(c+3) = 2 \pi hc+6\pi h

IgorLugansk [536]3 years ago
3 0

For this case we have the following function:

g (r) = 2 \pi * r * h

We must evaluate the function for different values:

g (4) = 2 \pi * (4) * h = 8 \pi*h\\g (\frac {3} {2}) = 2 \pi * (\frac {3} {2}) * h = 3 \pi*h\\g (2c) = 2 \pi * (2c) * h = 4 \pi * c * h\\g (c + 3) = 2 \pi * (c + 3) * h = 2 \pi * c * h + 6 \pi * h

Answer:

g (4) = 8 \pi*h\\g (\frac {3} {2}) =3 \pi*h\\g (2c) = 4 \pi * c * h\\g (c + 3) = 2 \pi * c * h + 6 \pi * h

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Step-by-step explanation:

3^3=27, 27-7=20, 20·5=100, 100/10=10.

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