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3 years ago

If the pet store had 10 more birds the number of dogs would be double the number of birds what numbers should be on the scale

Mathematics

2 answers:

Jet001 [13]3 years ago

8 0

Dogs vs birds ratio
1:2

frosja888 [35]3 years ago

4 0

If there were 10 dogs then there would be 20 birds

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Which number has the greatest absolute value? A) 15 B) 5 C) 0 D) −25

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Answer:

Step-by-step explanation:

Once the negative value is taken away, it's the largest number out of the bunch.

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3 years ago

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What is the probability that a marble chosen at random is

Brums [2.3K]

Answer:

$P=\frac{6}{11}$

Step-by-step explanation:

The probability can be defined as the ratio between the possible events and the total number of outcomes.

In this case, according to the image attached, the total number of outcomes is 11, because they are 11 marbles in total.

Now, the specific event is all shaded marbles or labeled with a multiple of 3. With this specific characteristics 6 marbles, because there are 5 shaded marbles and 6 is a multiple of 3. So, the possible events are 6.

Therefore, the probability is

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The right answer is the last choice.

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3 years ago

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Zina [86]

This is not formatted correctly.

76 degrees and 47 degrees?

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3 years ago

The debate team has m members. Each member sold 5 coupon books as a fundraiser. Write an expression that shows the number of cou

Igoryamba

The equation should be:
m x 5 = 5m

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3 years ago

The population of a particular type of bacteria is known to triple in 22 days. What is the daily growth rate

Paul [167]

Answer: ∛(3)

Step-by-step explanation:

Suppose that at day 0 the population was A.

at day 3, the population will be: 3*A

at day 6, the population will be 3*(3*A) = A*3^2

then, at day N = 3*n (where n = 0, 1, 2.....) the population will be:

P(N) = A*3^n

Particularly, if we take n = 1/3 we will have:

N = 3*1/3 = 1

This means that this is the first day after the day 0.

P(1) = A*3^(1/3)

(then in day one, the population grow by a factor of 3^(1/3))

N = 2 is when n = 2/3, then:

P(2) = A*3^(2/3)

The quotient between P(2) and P(1) is equal to the growth between day one and day two, this should be the same as the growth between day zero and day one.

A*3^(2/3)/(A*3^(1/3)) = 3^( 2/3 - 1/3) = 3^(1/3)

So we found that the daily growth rate is 3^(1/3) or ∛(3)

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3 years ago