So we are looking for the GCF which is the largest factor that the two numbers have in common, so you would want to circle all of the number that the two have in common. So it would be 2 twos and 2 X's (2,2,x,x). Which is the most numbers that the two have in common.

7 0

3 years ago

Please help me I can't fail! Okay, So I have this big algebra test that's worth 30% of my grade. Right now I have a 62 I need a

Andreyy89

Where? It won’t show!

5 0

3 years ago

Discuss the validity of the following statement. If the statement is always true, explain why. If not, give a counterexample.

Zarrin [17]

Correction:

Because F is not present in the statement, instead of working onP(E)P(F) = P(E∩F), I worked on

P(E∩E') = P(E)P(E').

Answer:

The case is not always true.

Step-by-step explanation:

Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.

And for any two mutually exclusive events, E and E',

P(E∩E') = 0

Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then

P(E)P(E') cannot be equal to zero.

P(E)P(E') ≠ 0

This makes P(E∩E') different from P(E)P(E')

Therefore,

P(E∩E') ≠ P(E)P(E') in this case.

8 0

3 years ago