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Paladinen [302]
3 years ago
11

Ms.Lamberson got a new puppy abd weighed it in September and October in September the Puppy Weighed9 and one Fourth pounds In Oc

tober the Puppy Weighed 11and One Half Pounds how much heavier was the puppy in October than it was in September
Mathematics
1 answer:
ddd [48]3 years ago
8 0

Answer: The puppy was 2.25\ lb havier in October that it was in September.

Step-by-step explanation:

You need to make the conversion from mixed numbers to decimal numbers. To do it, divide the numerator of the fraction by the denominator add the result to whole part number:

9\frac{1}{4}=9+0.25=9.25\\\\11\frac{1}{2}=11+0.5=11.5

The weight of the puppy in September was:

w_1=9.25\ lb

And its weight in October was:

w_2=11.5\ lb

Subtract its weight in September from its weight in October in order to find how much heavier the puppy was in October than it was in September:

w_2-w_1=11.5\ lb-9.25\ lb=2.25\ lb

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3 years ago
Ami'yan runs every day for exercise at a rate of 1 kilometer every 15 minutes. How many meters does he run in 1 hour? - Thank yo
Alona [7]

Answer:

The total distance covered in 1 hour  is 4000 meters.

Step-by-step explanation:

The distance Ami'yan runs is 15 minutes = 1 kilometer

Using the unit formula,

The distance ran in 1 minute = (\frac{1}{15} ) \textrm{Kilometer}

Now, 1 hour = 60 minutes

⇒The distance covered in 60 minutes =  60 x (Distance run in 1 minute)

                                                               = 60 \times \frac{1}{15}    = 4

So, the distance covered in 1 hour  = 4 kilometer

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Hence, the total distance covered in 1 hour  = 4000 meters.

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2 years ago
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siniylev [52]

Answer:

a, (x^2)^3 = x^6 = x^2.x^4

b, x^5·x^7 = x^12 = (x^3)^4

c, x^4·x^22 = x^26 = (x^2)^13

d, (x^2)^8 = x^16 = x^2.x^14

e, x^10/x^3 = x^7 = x^20.x^(-13)

f, x^(-3) = x^4.x^(-7)

g, 1/x^(-3) = x^3 = x^4.x^(-1)

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3 years ago
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ANTONII [103]

Answer:

D) y= 4x - 1

Step-by-step explanation:

We are basically trying to see which of the equations provided are true on both sides of the equal sign when you plug in the x and y values.

Let's start!

Choice A:

  plug in 0 for x and -1 for y

-1 = 4(0)

And you are left with...

-1 = 0

This equation is false! Therefore it does not match the function in the table

Choice B:

   plug in the values again

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Choice C:

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False!

Lastly...Choice D:

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So your answer is D

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