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Paladinen [302]
3 years ago
11

Ms.Lamberson got a new puppy abd weighed it in September and October in September the Puppy Weighed9 and one Fourth pounds In Oc

tober the Puppy Weighed 11and One Half Pounds how much heavier was the puppy in October than it was in September
Mathematics
1 answer:
ddd [48]3 years ago
8 0

Answer: The puppy was 2.25\ lb havier in October that it was in September.

Step-by-step explanation:

You need to make the conversion from mixed numbers to decimal numbers. To do it, divide the numerator of the fraction by the denominator add the result to whole part number:

9\frac{1}{4}=9+0.25=9.25\\\\11\frac{1}{2}=11+0.5=11.5

The weight of the puppy in September was:

w_1=9.25\ lb

And its weight in October was:

w_2=11.5\ lb

Subtract its weight in September from its weight in October in order to find how much heavier the puppy was in October than it was in September:

w_2-w_1=11.5\ lb-9.25\ lb=2.25\ lb

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<h2>         y = 6x - 1</h2>

Step-by-step explanation:

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(0, -1)    ⇒     x₁ = 0,  y₁ = -1

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The slope-intercept form of the equation of line is y = mx + b, where m is the slope and b is the y-intercept of the line.

(0, -1)    ⇒     x₀ = 0,  y₀ = -1      ⇒   b = -1

Therefore:

                 y = 6x - 1          ←  the slope-intercept form of the equation

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