The cost of one pound of peanuts is 60% of the cost of one pound of cashews. If one pound of cashews costs $2, what is the cost
1 answer:
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Answer:
Step-by-step explanation:
Total outcomes possible: 36
A. Divisible by 3
Possible options are:
3, 6, 9 and 12.
Possible outcomes for 3 are: {(1,2), (2,1)} Count 2
Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5
Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4
Possible outcomes for 12 are: {(6,6)} Count 1
Total count = 2 + 5 + 4 + 1 = 12
Probability of an event E can be formulated as:
B. Less than 7:
Possible sum can be 2, 3, 4, 5, 6
Possible cases for sum 2: {(1,1)} Count 1
Possible cases for sum 3: {(1,2), (2,1)} Count 2
Possible cases for sum 4: {(1,3), (3,1), (2,2)} Count 3
Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)} Count 4
Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5
Total count = 1 + 2 + 3 + 4 + 5 = 15
C. Divisible by 3 and less than 7:
Here, common cases are:
Possible outcomes for 3 are: {(1,2), (2,1)} Count 2
Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5
Answer:
Anything that does not cost more than $2,560.00
Step-by-step explanation:
Provided that Nikita is spending money that she had invested and the amount she collected over the period of 7 years. She can buy any item that costs no more than $2,560.00 but how?
It is a problem of simple interest:
Here the principal amount (P) = $2,000.00
Interest rate (r) = 4%
Time period (t) = 7 years
So, total amount that she would get by the end of 7 years is:
Plugging the values we get:
So the interest collected over 7 years is $560.00
Therefore, the total amount after 7 years is:
If Nikita is using this money then the most expensive item that she could buy will cost no more than $2,560.00.
<h3>Answer: Rhombus</h3>
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Reason:
Let's find the distance from A to B. This is equivalent to finding the length of segment AB. I'll use the distance formula.
Segment AB is exactly units long, which is approximately 4.1231 units.
If you were to repeat similar steps for the other sides (BC, CD and AD) you should find that all four sides are the same length. Because of this fact, we have a rhombus.
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Let's see if this rhombus is a square or not. We'll need to see if the adjacent sides are perpendicular. For that we'll need the slope.
Let's find the slope of AB.
Segment AB has a slope of 1/4.
Do the same for BC
Unfortunately the two slopes of 1/4 and 4 are not negative reciprocals of one another. One slope has to be negative while the other is positive, if we wanted perpendicular lines. Also recall that perpendicular slopes must multiply to -1.
We don't have perpendicular lines, so the interior angles are not 90 degrees each.
Therefore, this figure is not a rectangle and by extension it's not a square either.
The best description for this figure is a <u>rhombus</u>.