Answer:
The correct answer is-
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
2. Two genes, with a dominant allele at either or both loci.
Explanation:
The given information gives THE following data:
Dominant: Lancerate leaves - AABB
Recessive: normal leaves - aabb
F1 has - all Lacerated leaves - AaBb
F2 by selfing F1:
AB Ab aB ab
AB AABB AABb AaBB AaBb
Ab AABb AAbb AaBb Aabb
aB AaBB AaBb aaBB aaBb
ab AaBb Aabb aaBb aabb
Here, 15/16 = lacerate which is 0.94 which is equal to the value of lacerate given in the question - 249/265 = 0.94
And normal 1/16 = 0.062 is almost same as 16/265 = 0.060
Thus, the genotypes of -
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
<span>It is identical or nearly identical to the first DNA molecule.</span>
Answer:
It corresponds to a leaf tissue.
Explanation:
The composition of the leaf tissue, which absorbs sunlight, is observed in the process of photosynthesis. The epidermis, parenchyma, stoma, among other structures are observed.
I think it just shows how many people care about the cause and think it’s important. It can also raise money and awareness about it.
Answer:OWA OWA
Explanation:Thanks lol and if anyone can help me on my recent questions please thanks<3
