the pH during the titration of 40.00 mL of 0.1000 M HCl after adding 50 mL of 0.1000 M NaOH is pH = 13.39
NaOH + HCl → NaCl + H2O
40.00 ml 0.5M NaOH solution
mol NaOH = 40 ml / 1000 ml / L * 0.5 mol / L = 0.02 mol NaOH
25 mL 0.1 M HCl
mol HCl = 25 mL / 1000 mL / L * 0.1 mol / L = 0, 0025 mol
This reacts with 0.0025 mol NaOH
[NaOH] = 0.269 M
[OH-] = 0.269 M
pOH = - log 0.269
pOH = 13.43
You titrate with 30 mL 0.100 M HCl
Mol HCl = 30 mL / 1000 mL/L * 0.100 mol /L = 0.003 mol HCl
This will react with 0.003 mol NaOH
Mol unreacted NaOH = 0.02 mol - 0.003 mol = 0.017 mol NaOH in 40mL + 30 mL = 70 mL solution
Molarity of NaOH solution = 0.017 mol / 70 mL * 1000 mL/L = 0.243 M
[OH-] = 0.243 M
pOH = - log 0.243
pOH = 0.61
pH = 13.39
40 mL
Titration is defined as "the process of determining the amount of substance A by adding a measured amount of substance B, which is a titrator that reacts until an accurate chemical equivalence point is reached."
Learn more about titration here: brainly.com/question/186765
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Answer:
If your lab has litmus paper, you can use it to determine your solution's pH. When you place a drop of a solution on the litmus paper, the paper changes color based on the pH of the solution. Once the color changes, you can compare it to the color chart on the paper's package to find the pH.
Explanation:
A solution's pH will be a number between 0 and 14. A solution with a pH of 7 is classified as neutral. If the pH is lower than 7, the solution is acidic. When pH is higher than 7, the solution is basic. These numbers describe the concentration of hydrogen ions in the solution and increase on a negative logarithmic scale.
For example, If Solution A has a pH of 3 and Solution B has a pH of 1, then Solution B has 100 times as many hydrogen ions than A and is therefore 100 times more acidic.
C because I’m space there’s no gravity meaning things are weightless
Answer:
<h3>The answer is 1.59 cm³</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 12.5 g
density = 7.87 g/cm³
We have
We have the final answer as
<h3>1.59 cm³</h3>
Hope this helps you
Answer:
0.47dm³
Explanation
Given parameters :
Molarity of NaCl = 6.67M
Number of moles = 3.12mol
Volume of NaCl =?
Volume of NaCl = number of moles/Molarity
Volume of NaCl = 3.12mol/6.67M
Volume of NaCl = 0.47dm³