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Aleonysh [2.5K]
3 years ago
12

How does the chemical structure of water change when it changes state?

Chemistry
1 answer:
Bad White [126]3 years ago
4 0
When the water is heated, the water molecules bounce around and spread out.
When the water is normal, they are pretty close-knit but still flow around. 
When the water is frozen, they are frozen in place and do not move. 
I hope this helped :) 
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A solution containing CaCl2 is mixed with a solution of Li2C2O4 to form a solution that is 2.1 × 10-5 M in calcium ion and 4.75
Mkey [24]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

      [Ca^{2+}] = 2.1 \times 10^{-5} M

      [C_{2}O_{4}^{2-}] = 4.75 \times 10^{-5} M

      K_{sp} (CaC_{2}O_{4}) = 2.3 \times 10^{-9}

As expression for K_{sp} will be as follows.

                  K_{sp} = [Ca^{2+}][C_{2}O^{2-}_{4}]

                            = 2.3 \times 10^{-9}

And, expression for ionic product will be as follows.

                  Q = [Ca^{2+}][C_{2}O^{2-}_{4}]

                      = 2.1 \times 10^{-5} \times 4.75 \times 10^{-5}

                      = 9.975 \times 10^{-10}

Since, it is shown here that ionic product is less that solubility product. Hence, no precipitate will form.

Thus, we can conclude that nothing will happen since Ksp > Q for all possible precipitants.

3 0
3 years ago
A scientist is performing an experiment on a powder. Which of the following is a sign that a chemical change has definitely occu
n200080 [17]
The powder catches fire. The rest of the choices pertains to physical changes on the powder. When the powder catches fire a chemical change happens. For example, if the powder is organic, carbon dioxide and water will result during the combustion. 
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Two objects are brought into contact Object 1 has mass 0.76 kg, specific heat capacity 0.87) g'c and initial temperature 52.2 'C
taurus [48]

Answer:

T_F=77.4\°C

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:

Q_1=-Q_2

In terms of mass, specific heat and temperature change is:

m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)

Now, solve for the final temperature, as follows:

T_F=\frac{m_1C_1T_1+m_2C_2T_2}{m_1C_1+m_2C_2}

Then, plug in the masses, specific heat and temperatures to obtain:

T_F=\frac{760g*0.87\frac{J}{g\°C} *52.2\°C+70.7g*3.071\frac{J}{g\°C}*154\°C}{760g*0.87\frac{J}{g\°C} +70.7g*3.071\frac{J}{g\°C}} \\\\T_F=77.4\°C

Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.

Regards!

4 0
3 years ago
A water sample is found to contain 59 ppm
NeX [460]

Explanation:

k so basically u gotta do 59/1000000 then multiply that by 972 which gives u 0.057348

8 0
4 years ago
What is the layer of the earth?
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