Given a two-dimensional steady inviscid air flow field with no body forces described by the velocity field given below. Assuming
the density is constant find the pressure gradient in the x direction at a certain point specified by (x=3, y=2).
u = 2x
v = 3x - 2y
u = 2x
v = 3x - 2y
1 answer:
Answer:
the pressure gradient in the x direction = -15.48Pa/m
Explanation:
- The concept of partial differentiation was used in the determination of the expression for u and v.
- each is partially differentiated with respect to x and the appropriate substitution was done to get the value of the pressure gradient as shown in the attached file.
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Answer:
A) ( N ) = 1.54
B) N ( Goodman ) = 1.133, N ( Morrow) = 1.35
Explanation:
width of steel bar = 25-mm
thickness of steel bar = 10-mm
diameter = 6-mm
load on plate = between 12 kN AND 28 kN
notch sensitivity = 0.83
A ) Fatigue factor of safety based on yielding criteria
= δa + δm = = 91.03 + 227.58 = 490 / N
therefore Fatigue number of safety ( N ) = 1.54
δa (amplitude stress ) = kf ( Fa/A) = 2.162 * ( 8*10^3 / 190 ) = 91.03 MPa
A = area of steel bar = 190 mm^2 , Fa = amplitude load = 8 KN , kf = 2.162
δm (mean stress ) = kf ( Fm/A ) = (2.162 * 20*10^3 )/ 190 = 227.58 MPa
Fm = mean load = 20 *10^3
B) Fatigue factor of safety based on Goodman and Morrow criteria
δa / Se + δm / Sut = 1 / N
= 91.03 / 183.15 + 227.58 / 590 = 1 /N
Hence N = 1.133 ( based on Goodman criteria )
note : Se = endurance limit (calculated) = 183.15 , Sut = 590
applying Morrow criteria
N = 1 / ( δa/Se) + (δm/ δf )
= 1 / ( 91.03 / 183.15 ) + (227.58 / 935 )
= 1.35
Answer:
/****************** The code for a form application that uses radioButtons * *and displays new form based on the user selection *****************/
Using system;
Using system windows forms;
namespace CarDealer
{
Public partial class Form1 : Form
{
public Form1()
{
//default constructor to initialize components
InitializeComponent();
}
//when user clicks on the details button
private void detail_Click
(Object sender, EventArgs e)
{
if (model1,Checked)
{
Forms2 f = new Form2()
f.ShowDialog()
model1.Checked = false
}
if (model2.Checked)
{
Form3 f = new Form3();
f.ShowDialog();
model2.Checked = false;
}
if (model3.Checked)
{
Form4 f = new Form4();
f.ShowDialog();
model3.Checked = false;
}
}
}
}
Explanation:
Program plan
- Design form: Place label controls with text as select car model and one empty label control to display total price. Change front type and size from each other labels properties window.
- Add three radio buttons with text Renault Kwit, Tata Tiago, Mahindra KUV 100.
- Add button with text View Details.
- Add 3 new windows form from project menu for each car model.
- Change form name and respective car models.
- Place picturebox control to each form by using image property add .jpeg image and place label control containing price of each model to each form
- When user select car model and click on view details, new form containing car model details is displayed.
Form Design is attached below
