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if a voltage is applied to a capacitor, current flows easily at first and then slows as the capacitor becomes charged. Inductors
behave just the opposite, in that they reluctantly pass current when a voltage is first applied, and then the current passes easily as time passes. If the input voltage is suddenly raised from zero to some constant value, sketch the current in the capacitor, iC, and the inductor, iL, as a function of time. What is the steady-state current in the capacitor and inductor?
1 answer:
Answer: photo!
Explanation:
For the capacitor, the current as a function of time will be
I(t)=V/R e^(-t/RC)
In steady-state, time tends to infinite, so current tends to zero.
For the inductor, the current as a function of time is
I(t)=V/R (1-e^(-tR/L))
In steady-state, time tends to infinite, so current tends to V/R
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Explanation:
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Three methods are given to heat a particular house are as follows:
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Method (b)
Through electric resistance, this gives energy of amount $0.12/KWh.
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Change therm to kj in method ‘a’ as follows:
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Step2
Change kWh to kj in method ‘b’ as follows:
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Step3
Change kWh to kj in method ‘c’ as follows:
$/kj.
Thus, the method ‘a’ has least cost as compare to method b and c.
So, option ‘a’ is the cheapest for this house.