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Tatiana [17]
3 years ago
5

if a voltage is applied to a capacitor, current flows easily at first and then slows as the capacitor becomes charged. Inductors

behave just the opposite, in that they reluctantly pass current when a voltage is first applied, and then the current passes easily as time passes. If the input voltage is suddenly raised from zero to some constant value, sketch the current in the capacitor, iC, and the inductor, iL, as a function of time. What is the steady-state current in the capacitor and inductor?

Engineering
1 answer:
DENIUS [597]3 years ago
7 0

Answer: photo!

Explanation:

For the capacitor, the current as a function of time will be

I(t)=V/R e^(-t/RC)

In steady-state, time tends to infinite, so current tends to zero.

For the inductor, the current as a function of time is

I(t)=V/R (1-e^(-tR/L))

In steady-state, time tends to infinite, so current tends to V/R

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A labor-intensive process to manufacture a product has a fixed cost of $338,000 and a variable cost of $143 per unit. An automat
ozzi

Answer:

no of unit is 17941

Explanation:

given data

fixed cost = $338,000

variable cost = $143 per unit

fixed cost = $1,244,000  

variable cost = $92.50 per unit

solution

we consider here no of unit is = n

so here total cost of labor will be sum of fix and variable cost i.e

total cost of labor = $33800 + $143 n  ..........1

and

total cost of capital intensive  = $1,244,000 + $92.5 n   ..........2

so here in both we prefer cost of capital if cost of capital intensive less than cost of labor

$1,244,000 + $92.5 n  <  $33800 + $143 n

solve we get

n > \frac{906000}{50.5}

n > 17941

and

cost of producing less than selling cost so here

$1,244,000 + $92.5 n < 197 n

solve it we get

n > \frac{1244000}{104.5}  

n > 11904

so in both we get greatest no is 17941

so no of unit is 17941

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Answer:

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Explanation:

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Answer:

Check the explanation

Explanation:

1 -

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{

  int result = 0;

 

  //If round is divided by 3

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      result= 3;

  }

  //if round is not divided by 3 and is divided by 2

  else if(round%3 != 0 && round%2 == 0) {

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}

2-

public void playGame()

{

 

  //Initializing player 1 coins

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  for ( int round = 1 ; round <= maxRounds ; round++) {

     

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