Question

Find the exponential function passing through points (-1,4/3) and (3,108)

Answer 1

Answer:

its 152 i know cause i just did this....

Step-by-step explanation:

Answer 2

Answer:

An exponential function is in the general form   $\mathrm{y}=\mathrm{a}(\mathrm{b})^{\mathrm{x}}$

Explanation:

(x,y) = (-1,4/3) and (x,y)=  (3,108) are the given functions  

Therefore,  

    $\frac{4}{3}=a(b)^{-1}=\frac{a}{b}$

        $\frac{4}{3}=\frac{a}{b}$  - eq(1)

           $108=a(b)^{3}=a b^{3}=108-e q(2)$

Multiply both sides of the first equation by b to find that

       $\frac{4}{3} b=a$

Substituting in eq-2 we get

      $\frac{4}{3} b^{4}=108$

    $b^{4}=81$

  $\mathrm{b}=\pm 3$

  $\mathrm{b}=+3, \text { then } 108=\mathrm{a}(3)^{3}$

which gives a = 4,  

henceforth the equation becomes as   $\mathrm{y}=4(3)^{\mathrm{x}}$

    $\mathrm{b}=-3 \text { then } 108=\mathrm{a}(-3)^{3}$

which gives a = -4,  

henceforth the equation becomes as y =  $-4(-3)^{x}$

However! In an exponential function, b>0, otherwise many issues arise when trying to graph the function.

The only valid function is  $4(3)^{x}$