<span>Let x = third side
Using the Triangle Inequality theorem which states that the sum of two sides of a triangle must be longer than the third side and the difference of the two sides is the lower limit of the third side, the answer to your question is that the third side must be between 3 and 13, or written using inequalities, 3 < third side (or x) < 13 is the range.</span>
The result of the decrease of the number 14.4 by 0.2 of it is of 14.2.
<h3>What does it mean to decrease a number a by b of it?</h3>
The equivalent operation is the subtraction of a by b.
In this problem, we want to decrease the number 14.4 by 0.2 of it, hence the operation is:
14.4 - 0.2 = 14.2.
More can be learned about subtraction operations at brainly.com/question/4721701
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Answer:
Step-by-step explanation:
The third side could have dimension x
32 - 27 < x < 32 + 27
5 < x < 59
There are a few special triangles
Equilateral triangle could have legs
27, 32, <u>27</u>
or
32, 27,<u> 32</u>
A right triangle could have the third side
√(27² + 32²) = <u>√1753</u> which is about<u> 41.87</u>
or
√(32² - 27²) = <u>√295</u> which is about <u>17.18</u>
Notice all these fit within the original limits specified.
Answer:
534061 miles ²
Step-by-step explanation:
I did 1033x1034 and got 1068122 and then divided by 2 to get 534061 miles
So, pretend this is your x-axis and y-axis:
I
I
(-2,7) • I
I
I • (2, 5)
I
I
I
I
_________________I____________________
I
I
I
TO GET FROM POINT (-2, 7) TO POINT (2, 5), WE MOVE DOWN 2 AND OVER 4, SO THE SLOPE IS -1/2. IF WE FOLLOW THAT SLOPE AND MOVE DOWN 1 AND OVER 2 FROM THE FIRST POINT OF (-2, 7), WE WILL LAND ON A POINT LOCATED AT (0, 6), WHICH WOULD BE THE "Y-INTERCEPT". WE WERE JUST ABLE TO CALCULATE THE SLOPE OF THE LINE AND THEN USE THE SLOPE TO FIND THE INTERCEPT. SO, THE "SLOPE-INTERCEPT" FORM OF THE EQUATION FOR THIS LINE IS:
y = -1/2x + 6
TO RE-WRITE THIS IN STANDARD FORM, WE JUST WANT TO MOVE THE X VARIABLE OVER TO THE LEFT WITH THE Y VARIABLE, SO:
y = -1/2x + 6
+1/2x + 1/2x
1/2x + y = 6 .... and that is your answer!