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3 years ago

How do you simplify the following

1 answer:

8 0

It is 2i I standing for imaginary since it is a negative

square root of -1×4

4 square rooted is 2

and a negative number square rooted is i

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A dilation with a scale factor of 4 is applied to the three line segments shown. The resulting images are P'Q', A'B', and M'N' D

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Answer:

1st into the 3rd 2nd into 1st 3rd into 3rd

Step-by-step explanation:

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2 years ago

How can I rewrite this in exponential form and then evaluate it?

Vedmedyk [2.9K]

QUESTION:- EVALUATE THE EXPRESSION

EXPRESSION:-

${( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2}$

<h3>ANSWER-></h3>

${( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2} \\ {( {27 {a}^{3} {b}^{4} } )}^{ \frac{2}{6} } \\ {({27 {a}^{3} {b}^{4} } )}^{ \frac{ \cancel{2}}{ \cancel6 {}^{ \: 3} } } \\ {(27)}^{ \frac{1}{3} } {a}^{ \frac{3}{3} } {b}^{ \frac{4}{3} } \\{(3)}^{ \frac{ \cancel3}{ \cancel3} } {a}^{ \frac{ \cancel3}{ \cancel3} } {b}^{\frac{3 + 1}{3} } \\3a {b}^{ \frac{ \cancel3}{ \cancel3} } {b}^{ \frac{1}{3} }$ $\\ ANSWER->3ab \sqrt[3]{b} \: \: \: \: \: or \: \: 3a {b}^{ \frac{4}{3} }$

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2 years ago

What is the distance between point A and point B?what is the ordered pair for each of the points plotted above?

Alekssandra [29.7K]

Answer:

A: (0,0), B: (3, -4), 5 units

Step-by-step explanation:

A: (0,0), B: (3, -4)

To find the distance, use the distance formula. Square-root((0-3)^2+(0-(-4))^2) ---> Square-root((-3)^2 + 4^2) ---> Square-root(9+16) ---> Square-root(25) ---> 5units.

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3 years ago

A boat goes 3/4 hours with a speed of 8mph and 1/3 hours with a speed of 12mph. What distance did the boat cover in all this tim

Ludmilka [50]

Answer:

<em>10 miles</em>

Step-by-step explanation:

Distance d = v t

v - speed/velocity

t - time

<em>d</em> = $\frac{3}{4}$ (8) + $\frac{1}{3}$ (12) = 6 + 4 = <em>10 miles</em>

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3 years ago

Sarah answered 24 questions on her test correctly and earned an 80%. How many questions were on the test?

MaRussiya [10]

Answer:

43 questions in total

Step-by-step explanation:

the original equation with the unknown (total number of questions on the test) will look like this

$\frac{total \: number \: of \: questions \: on \: exam}{24 \: answered \: questions} = 80\%$

we know this because to work out a percentage in the 1st place you need the total ÷ number (in this case it's ÷ how many questions out of the total she did answer)

now you rearrange.

you need to move the 24 to get the total on it's own here's how you do it

$\frac{tot \: num \: of \: qs}{24} \times 24 = 80\% \times 24$