How do you simplify the following

1 answer:

8 0

It is 2i I standing for imaginary since it is a negative

square root of -1×4

4 square rooted is 2

and a negative number square rooted is i

You might be interested in

Find domain of y=rad20-6x

Evgesh-ka [11]

Domain, on an "even root" context, means, an even root cannot have a negative radicand, since say for example $\bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25$

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

$\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x$

now, if "x" is 10/3, let's see $\bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0$

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example $\bf x=\frac{11}{3}
\\\\\\

\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}$

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish

5 0

3 years ago

Can someone help me solve for x in this equation?? 25+3.50x < 17+7.50x

Lelu [443]

So we want to solve like if it was just a basic equation. We start with 25+3.50x<17+7.50x and get rid of our smallest x. That means we get rid of the 3.50x by subtracting from both sides and our new equation is 25<17+4x. Let’s get our x by itself shall we, so let’s subtract 17 from both sides and we get 8<4x. Finally all we do is divide by 4 and just like that 2

4 0

3 years ago

If f(x) = 4x + 2, what is the value of f(3)? O 8 O 14 O 45 O 66

lutik1710 [3]

Answer:

Step-by-step explanation:

5 0

3 years ago

4 lb. 8 oz. − 1 lb. 2 oz. =

saw5 [17]

4.8 takeaway 1.2 equals 3.6

8 0