Half life formula
The number of unstable nuclei remaining after time t can be determined according to this equation:
N(t) = N(0) * 0.5^(t/T)
where:
N(t) is the remaining quantity of a substance after time t has elapsed.
N(0) is the initial quantity of this substance.
T is the half-life.
It is also possible to determine the remaining quantity of a substance using a few other parameters:
N(t) = N(0) * e^(-t/τ)
N(t) = N(0) * e^(-λt)
τ is the mean lifetime - the average amount of time a nucleus remains intact.
λ is the decay constant (rate of decay).
All three of the parameters characterizing a substance's radioactivity are related in the following way:
T = ln(2)/λ = ln(2)*τ
How to calculate the half life
Determine the initial amount of a substance. For example, N(0) = 2.5 kg.
Determine the final amount of a substance - for instance, N(t) = 2.1 kg.
Measure how long it took for that amount of material to decay. In our experiment, we observed that it took 5 minutes.
Input these values into our half life calculator. It will compute a result for you instantaneously - in this case, the half life is equal to 19.88 minutes.
If you are not certain that our calculator returned the correct result, you can always check it using the half life formula.
The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases.
Answer:
The correct answer is d Bill"s plasma contain B antibodies
Explanation:
As Bill"s plasma contain B antibodies that"s why his blood cells do not aggutinate when mixed with anti B serum.
Answer:
- The former bacteria, Pseudomonas sp., has the ability to utilize benzoate as a source of carbon.
- Pseudomonas sp. can also migrate in the direction of areas with higher oxygen concentrations.
Whereas the latter, Bacillus sp., does not possess these characteristics.
Explanation:
The two traits mentioned above will provide the basis upon which the strategy for enrichment can be made.
Answer:
Frogs have some important internal and external structures that helps them to survive, grow and reproduce. Frog have almost similar internal anatomy to humans.
Frogs have the ability to respire through both lungs and skin. Skin is the external structure that helps them to respire in aquatic ecology.The skins helps to dissolves oxygen from the air and water and releases carbon-dioxide. Skin helps frogs to respire under water but if water do not have enough oxygen, frogs will drown.
<em>An internal structure called liver is present in frog same as human beings. </em> The liver releases chemical called bile that are utilized in digestion of fat and then emptied into the small intestine.
Hence, skin and liver are important for the survival of frog.
