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4 years ago

7

You intend to plant 5 acres of corn this spring. The seed corn will cost $210 for the field, the fertilizer will cost $800, and

the chemicals will cost $120. If you get a yield of 85 bushels per acre, how much money will your corn cost to produce?

1 answer:

Inessa [10]4 years ago

5 0

Answer:

$1000

Explanation:

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Which of these resources are renewable? Check all that apply. natural gas wind minerals forests tides geothermal energy

PolarNik [594]

Here is a list of some renewable resources, I hope these help answer the question, or help to answer it.

-ethanol

-hydropower

-geothermal power

-wind energy

-solar energy

-biomass

(Biomass refers to organic material from plants and animals)

4 0

3 years ago

Word equations- Please help ASAP

nekit [7.7K]

Answer:

See answer below

Explanation:

In this case, you just need to use any acid you want (Like HCl, or H₂SO₄) to do this exercise.

You are given a sample of what you have to do which is:

Acid + metal ------> Salt + hydrogen

As you can see, an acid like the ones I wrote above, have hydrogen atoms, so you should put the hydrogen there. As for the part of salt, you just need to draw the corresponding salt that is formed when the acid reacts with the metal, and write it's name.

Let's do all three equations for you to a better understanding. For all the given examples, I will use HCl as acid, and i will explain one reaction cause the other two reactions happens the same thing, only with a different metal.

1. 2HCl + Zn ------> ZnCl₂ + H₂

As you can see, we just have a displacement reaction where the metal displaces the position of the hydrogen to form the salt and the hydrogen leaves the molecule as a gaseous molecule. Written in words it would be:

Hydrochloric acid + Zinc ----> Zinc chloride + hydrogen

2. 2HCl + Pb -------> PbCl₂ + H₂

Hydrochloric acid + lead ------> Lead (II) chloride + hydrogen

3. 2HCl + Fe -------> FeCl₂ + H₂

Hydrochloric acid + iron ------> Iron (II) chloride + hydrogen

Hope this helps

4 0

3 years ago

CaCO3(s) ∆→CaO(s) + CO2(g).

sveta [45]

Answer:

74.9%.

Explanation:

Relative atomic mass data from a modern periodic table:

Ca: 40.078;
C: 12.011;
O: 15.999.

What's the <em>theoretical</em> yield of this reaction?

In other words, what's the mass of the CO₂ that should come out of heating 40.1 grams of CaCO₃?

Molar mass of CaCO₃:

$M(\text{CaCO}_3) = 40.078 + 12.011 + 3 \times 15.999 = 100.086\;\text{g}\cdot\text{mol}^{-1}$ .

Number of moles of CaCO₃ available:

$\displaystyle n(\text{CaCO}_3) =\frac{m}{M} = \frac{40.1}{100.086} = 0.400655\;\text{mol}$ .

Look at the chemical equation. The coefficient in front of both CaCO₃ and CO₂ is one. Decomposing every mole of CaCO₃ should produce one mole of CO₂.

$n(\text{CO}2) = n(\text{CaCO}_3)= 0.400655\;\text{mol}$ .

Molar mass of CO₂:

$M(\text{CO}_2) = 12.011 + 2\times 15.999 = 44.009\;\text{g}\cdot\text{mol}^{-1}$ .

Mass of the 0.400655 moles of $\text{CO}_2$ expected for the 40.1 grams of CaCO₃:

$m(\text{CO}_2) = n\cdot M = 0.400655 \times 44.009 = 17.632\;\text{g}$ .

What's the <em>percentage</em> yield of this reaction?

$\displaystyle \textbf{Percentage}\text{ Yield} = \frac{\textbf{Actual}\text{ Yield}}{\textbf{Theoretical}\text{ Yield}}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} = \frac{13.2}{17.632}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} =74.9\%$ .

7 0

3 years ago

What quantity of potassium phosphate, in grams, is required to prepare 500.0 ml of solution where you the concentration of potas

Readme [11.4K]

Answer: 3.54

Explanation:

You're forgetting to divide by 3 for the 3 moles of potassium that are in potassium phosphate.

Potassium Phosphate= K3PO4

3 0

3 years ago

Do step 3 as outlined in the lab guide. Record your results in the appropriate blanks.

PolarNik [594]

Explanation:

Do the step 3 as outlined in the lab guide. record your results in the appropriate blank.

D

8 0

3 years ago