Answer:
Molar masses of X and Z
Explanation:
To determine the mole percent of a mixture ( mole percent of unknown metals = number of mole of each of them divided the total of both the unknown salt × 100) since the percent by mass is know; we the molar mass of X and Z
mole = mass given / molar mass
Answer:
2KOH + 3co2 ------->2ксоз + 2Н20
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Answer:
Volume of ammonia 3 L.
Explanation:
Given data:
Temperature = 25°C ( 25+273= 298 k)
Pressure = 99.5 kpa (99.5/101 = 0.98 atm)
Volume of nitrogen = 1.50 L
Volume of ammonia = ?
Solution:
Chemical equation:
N₂ + 3H₂ → 2NH₃
Moles of nitrogen:
PV = nRT
n = PV/RT
n = 0.98 atm × 1.50 L / 0.0821 atm. L/mol. K × 298 K
n = 1.47 /24.5 /mol
n = 0.06 mol
Now we will compare the moles of nitrogen with ammonia.
N₂ : NH₃
1 : 2
0.06 : 2×0.06 = 0.12 mol
Volume of ammonia:
PV = nRT
V = nRT/P
V = 0.12 mol× 0.0821 atm. L/mol. K × 298 K/ 0.98 atm
V = 2.9 atm. L /0.98 atm
V = 3 L
