Do step 3 as outlined in the lab guide. Record your results in the appropriate blanks.
1 answer:
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Answer : The correct answer for molarity of MgCl₂ solution is 0.67 M.
Molarity :
It expresses concentration of any solution . It can be defined as mole of solute present in volume of solution in Liter .
It uses unit M or
It can be formulated as :
Given : mol of MgCl₂ (solute ) = 0.50 mol
Volume of solution = 750 mL
Following steps can be done :
Step 1 ) To convert volume of solution from mL to L
1 L = 1000 mL
Volume of solution = 0.750 L
Step 2) To find molarity
Plugging mole of solute and volume of solution in molarity formula as :
Hence molarity of MgCl₂ solution is 0.67 M
Step 1
<em>The reaction involved:</em>
CO + 2 H2 → CH3OH (completed and balanced)
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Step 2
<em>Data provided:</em>
19.7 g H2 (the limiting reactant)
Excess reactant = CO
144.5 g CH3OH = actual yield
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<em>Data needed:</em>
The molar masses of:
H2) 2.00 g/mol
CH3OH) 32.0 g/mol
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Step 3
The theoretical yield:
By stoichiometry,
CO + 2 H2 → CH3OH (The molar rate between H2 and CH3OH = 2:1)
2 x 2.00 g H2 --------- 32.0 g CH3OH
19.7 g H2 --------- X
X = 19.7 g H2 x 32.0 g CH3OH/2 x 2.00 g H2
X = 157.6 g CH3OH (The theoretical yield)
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Step 4
The % yield is defined as follows:
Answer: d. 93% (it is the nearest value in comparison to my result)
Answer:
hydrogen=161mmHg
Explanation:
