All categories

3 years ago

5. What is the density of water in g/mL? Why?

Chemistry

1 answer:

goldfiish [28.3K]3 years ago

7 0

Answer:

1g/ml @ 4 degrees C by definition

Explanation:

You might be interested in

g Calculate the theoretical yield (in grams) of your product if you start with 0.50 grams of E-stilbene. The molecular weight of

sattari [20]

Answer:

0.9433g

Explanation:

Theoretical yield is defined as the mass produced assuming all reactant reacts producing the product.

Assuming the reaction is 1:1, we need to find the moles of E-stilbene (Reactant). If all reactant reacts, the moles of E-stilbene = Moles of product.

Using the molar mass of the product we can find the theoretical yield as follows:

Moles E-stilbene:

0.50g * (1mol/180.25g) = 0.00277 moles = Moles Product

Mass Product = Theoretical yield:

0.00277 moles * (340.058g/mol) = 0.9433g

4 0

3 years ago

Hello summer roses~ help me with these questions

Olegator [25]

Answer:

The process of "slaking" of lime refers to the use of excess water for hydration. balanced equation: CaO + H₂0 = Ca(OH)₂ + heat released

First lets know which oxide is quick lime - CaO, is basic in nature as a result it combines with acidic oxides using heat. For example we are gonna make it react with silicon dioxide which is a very weak acid: CaO + SiO₂ → CaSiO₃

Hope this helps ~

3 0

3 years ago

Scenario: You are testing two different

chubhunter [2.5K]

Answer:1 × 10-8 M

Explanation:

5 0

3 years ago

Read 2 more answers

Am I incorrect ? Or nah?

Mademuasel [1]

I think so... I'm currently learning this too but you should be correct

4 0

3 years ago

Read 2 more answers

Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)

Reptile [31]

Answer: The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]$

For the given chemical reaction:

$C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]$

We are given:

$\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J$

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

4 0

3 years ago

5. What is the density of water in g/mL? Why?​

5. What is the density of water in g/mL? Why?