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Delvig [45]
2 years ago
8

Select the correct solution for 12x = 60 (A) X = 1/5 (B) X = 48 (C) X = 5 (D) X = 72

Mathematics
1 answer:
Georgia [21]2 years ago
4 0
The answer is c x= 5
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The 59th and 4th team of an Ap are - 61 and 64 respectively. Show that the common differences is - 2.5 and 23rd term is 16.5​
Mnenie [13.5K]

Answer:

See answers below

Step-by-step explanation:

T59 = a+58d = -61

T4 = a+3d = 64.

Subtract

58d-3d = -61-64

-55d = -125

d =125/55

d = 25/11

Get a;

From 2

a+3d = 64

a+3(25/11) = 64

a = 64-75/11

a = 704-75/11

a = 629/11

T23 = a+22d

T23 = 629/11+22(25/11)

T23 = 1179/11

3 0
3 years ago
There are (43)2 ⋅ 40 strawberries on a farm. What is the total number of strawberries on the farm
WINSTONCH [101]

There are 3,440 strawberries on the farm.

Brainliest please :)

7 0
3 years ago
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Freddy is driving from home to his grandfather's house, which is 174 miles away. He drives at an average rate of 58 miles per ho
Liono4ka [1.6K]
If n = number of hours and the equation is 174 + 58n then the answer is 3 hours

174 = 58n
   
     ÷  58

3  =  n
5 0
2 years ago
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Encuentra la ecuacion de la parabola con vertice en el origen y foco en las cordenadas 0,1en su forma ordinaria y general
marusya05 [52]

Answer:

x^{2}=4y

y=\frac{1}{4}x^{2}

Step-by-step explanation:

Forma ordinaria

La ecuación de la parabola de manera ordinaria está dada por:

(x-h)^{2}=4p(y-k) (1)  

Donde:

  • (h,k) es la coordenda del vértice, en nuestro caso (0,0) ya que está en el origen.
  • (h,k+p) es la coordenda del foco, en nuestro caso (0,1).

Por lo tanto h = 0, k = 0 y p = 1.

Remplazando estos valores en la ecuación de la parábola, tenemos:

(x-0)^{2}=4*1(y-0)

x^{2}=4y (2)

 

Forma general  

La forma general de una parábola esta dada por la siquiente ecuación

y=ax^{2}+bx+c

Reordenando la ecuación (2) tenemos:

y=\frac{1}{4}x^{2}

Espero esto te haya ayudado!

5 0
3 years ago
I need help with geometry
Vilka [71]
If i’m not wrong the answer should be B
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3 years ago
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