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3 years ago

Complete the equivalent equation for –7x – 60 = x2 + 10x. (x + )(x + ) = 0 What are the solutions of –7x – 60 = x2 + 10x? x =

Mathematics

2 answers:

umka21 [38]3 years ago

7 0

It is positive five and positive 12. thats the top part
the bottom part is negative 5 and negative12

anygoal [31]3 years ago

6 0

First get them all on one side
add 7x+60 to both sides
0=x^2+17x+60
now factor
what 2 numbers mutltiply to get 60 and add to get 17?
5 and 12
0=(x+5)(x+12)
set each to zero

0=x+5
-5=x

0=x+12
-12=x

the factored form is (x+5)(x+12)=0
the solutions are x=-12 and -5

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NEED HELP ASAP!!!!!!! WILL MARK CORRECT ANSWER BRAINLIEST!!!!

Ganezh [65]

Answer:

(x + 1)² + (y - 1)² = 1.5625

Step-by-step explanation:

From the picture we see:

The radius is 5 units. Each unit is .25 so the radius is 1.25.

The centre or middle M= ( -1, 1 )

Circle with centre M and radius r :

(x - xM)² + (y - yM)² = r²

xM = -1

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r = 1.25

(x - (-1))² + (y - 1)² = (1.25)²

(x + 1)² + (y - 1)² = 1.5625

6 0

4 years ago

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

Step-by-step explanation:

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

Hint: sin is only positive in Quadrants I and II

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

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$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

Hint: sin and cos are only opposite signs in Quadrants II and IV

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

3 years ago

Can anyone help me !

murzikaleks [220]

Answer:

I think it's AB=BC.

Step-by-step explanation:

*I'm not in college, nor anywhere near college-level math, just a heads-up.*

Anyway, here's what I think. I turned my head around a bit to different angles, and I noticed the angle AB is the exact same length as BC, and both make the triangle a right angle. Try it if ya want, and see what happens. Sorry if this's wrong. I do hope it helps!

4 0

4 years ago

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It cost $44.88 to buy 12 gallons of gas.What was the cost per gallon of gas?

Natali [406]

Answer:

$3.74 per gallon

Step-by-step explanation:

1. Divide $44.88 by 12

2. The answer will be 3.74

3. Each gallon will cost $3.74

4 0

4 years ago

What does (0.6) squired 2 equal

wlad13 [49]

Answer:

.36

Step-by-step explanation:

4 0

3 years ago