Answer:
![y=[1]cos([\frac{2\pi }{3}]x)](https://tex.z-dn.net/?f=y%3D%5B1%5Dcos%28%5B%5Cfrac%7B2%5Cpi%20%7D%7B3%7D%5Dx%29)
Step-by-step explanation:
Looking at the graph, we can see the domain to be from (0 , 2π).
Now we have to find one period that corresponds to cos(x).
The half-period of cos(x) for this graph appears to be pi/3 and adding another pi/3 gets us 2pi/3 to be our cosine period.
b = 2pi/3
a is the same range as cos(x). Range: (0,0)
y = [a] * cos ([b]*x)
y = [1] * cos([2pi/3]x)
<h2>Vertical distance gained from takeoff is 493.72 ft</h2>
Step-by-step explanation:
Refer the figure.
Horizontal distance = AB = 2800 ft
Angle = ∠B = 10°
We need to find AC that is h.
We have
Vertical distance gained from takeoff = 493.72 ft
Answer:
I = P/(RT)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
P = IRT
<u>Step 2: Solve for </u><em><u>I</u></em>
- [Division Property of Equality] Divide RT on both sides: P/(RT) = I
- Rewrite/Rearrange: I = P/(RT)
M is for slope
b is y intercept
and use equation y=mx+b
branliest please
EH i think b cause the nicle is the point
