The solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
<h3>What are linear equations?</h3>
Linear equations are equations that have constant average rates of change, slope or gradient
<h3>How to determine the solution to the system?</h3>
A system of linear equations is a collection of at least two linear equations.
In this case, the system of equations is given as
2x- y = 3
y - x = 1
Make y the subject in the second equation, by adding x to both sides of the equation
y - x + x = x + 1
This gives
y = x + 1
Substitute y = x + 1 in 2x- y = 3
2x- x - 1 = 3
Evaluate the like terms
x = 4
Substitute x = 4 in y = x + 1
y = 4 + 1
Evaluate
y = 5
Hence, the solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
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It might be 63 and 27 but if im wrong love me (plz dont really love me )
Answer:
0.5*13*15 = 97.5 square units
Step-by-step explanation:
If the diagonals of the rhombus are 13 and 15 then its area is 0.5*13*15 = 97.5 square units
Hello there, and thank you for posting your question here on brainly.
A trapezoid is not possible to have for obtuse because it would look more like a diamond. Also, if it had 4 obtuse angles, it would have 6 sides.
Hope this helped!! ☺♥
When you get to the point where the width is larger than the length, you can stop because you have exhausted all the possibilities. The greatest area will be the rectangle that is closer in to a square than any of the others.
