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Salsk061 [2.6K]
3 years ago
13

What is the answer for this problem in the picture

Mathematics
2 answers:
sdas [7]3 years ago
8 0

Answer:

The correct answer is third option

8x⁴yz⁴√2yz

Step-by-step explanation:

It is given that,

√128x⁸y³z⁹

<u>To find the equivalent of √128x⁸y³z⁹</u>

We have 128 = 2⁷

x⁸ = (x⁴)², y³ = y² * y and z⁹ = (z⁴)² * z

√128x⁸y³z⁹ = √(2⁷ * (x⁴)² * y²y * (z)⁴)²z)

  = 2³x⁴yz⁴√(2 * y * z)

 = 8x⁴yz⁴√2yz

Therefore the correct answer is third option

DENIUS [597]3 years ago
4 0

<u>Answer:</u>

The correct answer option is = 8 x ^ 4 y z ^ 4 \sqrt{2yz}.

<u>Step-by-step explanation:</u>

We are given the following expression and we are to simplify it and determine whether which of the given expressions is equivalent to it, assuming y\geq 0 and z\geq 0:

\sqrt { 128 x ^ 8 y ^ 3 z ^ 9 }

Breaking the terms to get:

\sqrt { 128 x ^ 8 y ^ 3 z ^ 9 }=8\sqrt{2yz} \times x^{8\times\frac{1}{2} } \times y^{2\times \frac{1}{2} } \times z^{8\times \frac{1}{2} }

= 8 x ^ 4 y z ^ 4 \sqrt{2yz}

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A function gives for each element of the domain only one element of the range.

Step-by-step explanation:

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Use each model to predict the life expectancy of residents of a country for which the average annual income is $80,000
Mandarinka [93]

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The life expectancies of the models are given as:

y =69.9352 + 0.1530\times (income) --- model 1

y =4.2436 + 0.0021\times (income) --- model 2

y =4.1393 + 0.0603\times (income) --- model 3

Given that the average annual income is $80,000;

We simply substitute 80000 for income in the equations of the three models.

So, we have:

<u>Model 1</u>

y =69.9352 + 0.1530\times (income)

y =69.9352 + 0.1530\times 80000

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<u>Model 2</u>

y =4.2436 + 0.0021\times (income)

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<u>Model 3</u>

y =4.1393 + 0.0603\times (income)

y =4.1393 + 0.0603\times 80000

y =4828.1393

Hence, the life expectancies are 12309.9352, 172.2436 and 4828.1393

Read more about linear models at:

brainly.com/question/8609070

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