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3 years ago

Find the area of the following figure.

Mathematics

1 answer:

dem82 [27]3 years ago

7 0

Answer:

the answer is 17.6cm2 ..

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In a recent year, a sample of grade 8 Washington State public school students taking a mathematics assessment test had a mean sc

Daniel [21]

Answer:

The number is $N =1147$ students

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 281$

The standard deviation is $\sigma = 34.4$

The sample size is n = 2000

percentage of the would you expect to have a score between 250 and 305 is mathematically represented as

$P(250 < X < 305 ) = P(\frac{ 250 - 281}{34.4 } < \frac{X - \mu }{\sigma } < \frac{ 305 - 281}{34.4 } )$

Generally

$\frac{X - \mu }{\sigma } = Z (Standardized \ value \ of \ X )$

$P(250 < X < 305 ) = P(-0.9012< Z$

$P(250 < X < 305 ) = P(z_2 < 0.698 ) - P(z_1 < -0.9012)$

From the z table the value of $P( z_2 < 0.698) = 0.75741$

and $P(z_1 < -0.9012) = 0.18374$

$P(250 < X < 305 ) = 0.75741 - 0.18374$

$P(250 < X < 305 ) = 0.57$

The percentage is $P(250 < X < 305 ) = 57\%$

The number of students that will get this score is

$N = 2000 * 0.57$

$N =1147$

6 0

3 years ago

Gabriella is x years old. Her sister, Felicia, is six years older than she is. Their mother is twice as old as Felicia. Their au

Yuri [45]

G = x
Felicia is Gabriella's age + 6
F = x + 6
Their mother is twice Felicia's age
M = 2(x + 6) or 2x + 12
Tanya is the age of their mother plus Gabriella's age
A = 2x + 12 + x = 3x + 12
3x + 12

7 0

3 years ago

31<br>Write as a mixed number.<br>Give your answer in its simplest form.

makvit [3.9K]

Six divided by five maybe and add a 1

4 0

2 years ago

Find the arc length and area of a sector with radius R =60 inches and central angle equals 30° round your answer to the nearest

Black_prince [1.1K]

Answer:

(a)31.42 inches

(b)942.48 Square Inches

Step-by-step explanation:

Given a sector of a circle with the following dimensions:

Radius of the circle =60 inches

Central Angle of the sector =30°

(a)Arc Length

Arc Length $=\dfrac{\theta}{360^\circ}X2\pi r$

$=\dfrac{30}{360^\circ}X2*60*\pi\\\\=10\pi\\\\=31.42$ Inches (correct to the nearest hundredth)$

(b)Area of the sector

Area of the sector $=\dfrac{\theta}{360^\circ}X\pi r^2$

$=\dfrac{30}{360^\circ}X\pi*60^2\\\\=300\pi\\\\=942.48$ Square Inches (correct to the nearest hundredth)$

3 0

3 years ago

Read 2 more answers

Which of the following best states the author's purpose?

Anastasy [175]

The answer is the second one

5 0

2 years ago