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3 years ago

How to solve for y with 9x-y=45?? Help!!

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

I think that's the answer

mojhsa [17]3 years ago

3 0

Isolate the y. Note the equal sign. What you do to one side, you do to the other.

First, subtract 9x from both sides

9x (-9x) - y = 45 (-9x)

-y = -9x + 45

Next, divide - 1 from both sides to isolate the y.

(-y)/-1 = (-9x + 45)/-1

y = 9x - 45

y = 9x - 45 is your answer

hope this helps

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gtnhenbr [62]

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3 years ago

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$\%Tip = 13.04\%$

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8 0

2 years ago

Can somebody please help me

guajiro [1.7K]

Here is your answer

B. (12,30)

REASON:

Given,

$y= 2x+6$ .......(i)

$3x-y= 6$ .......(ii)

Putting the value of y from eq.i in eq.ii we get

$3x-(2x+6)=6$

$3x-2x-6=6$

$=6+6$

$x=12$

Putting x=12 in eq.i we get

$y= 2x+6$

$y= 2×12+6$

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$y= 30$

So,

$\bold{x=12 and y= 30}$

Hence answer is (12,30) in which x=12 and y=30

HOPE IT IS USEFUL

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3 years ago

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3 years ago

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kramer

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Step-by-step explanation:

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2 years ago

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