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katen-ka-za [31]
3 years ago
9

Given that a­­^b = x, evaluate the following: 2a^3b+a^2b+a^b

Mathematics
1 answer:
Luda [366]3 years ago
8 0

Answer:

2*x^3 + x^2 + x

Step-by-step explanation:

a­­^b = x

Then,

a­­^(2b) = a­­^b*a­­^b = x* x = x^2

a^(3b)  = a­­^b*a­­^b*a­­^b = x*x*x = x^3

2*(a^3b) + (a^2b) + (a^b)

= 2*(x^3) + (x^2) + (x)

= 2*x^3 + x^2 + x

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Z varies directly as x2. If z = 16 when x = 2, find z when x = 5.<br> ...<br> Z=
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Answer:

100

Step-by-step explanation:

it is a bit unclear to me, what that problem description means.

if I understand it correctly, than z is directly depending on x².

so, z = 16 for x = 2. x² = 4

I pondered a little bit, as there are several possibilities to connect 16 with 4 as a driving factor (e.g. 2⁴ = 16, 4×4 = 16, 12 + 4 = 16).

I decided to go with the simplest interpretation with the usual meaning of "varies" (multiplication) : 4×x²

that would mean

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3 years ago
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