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4 years ago

Determine if the following statements are sometimes,never, or always true

1 answer:

6 0

1. always true
2. always true? (not 100% sure)
3. sometimes true
4. i don’t know, sorry
hope this helps a little bit! sorry i couldn’t help with all of them

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15) Jeremy is grocery shopping. He has $75 in his checking account and has already spent $53.86 on food. Which inequality repres

IgorC [24]

B), A),D), and I dontknow how to answer the last one

5 0

4 years ago

Read 2 more answers

Nick has $7.00. Bagels cost $0.75 each, and a small container of cream cheese costs $1.29. Write an inequality to find the numbe

saw5 [17]

Answer:

7 IS LESS THAN OR EQUAL TO 7-.75X+1.29

Step-by-step explanation:

X IS THE NUMBER OF BAGELS BOUGHT

3 0

3 years ago

GREYUIT [131]

Answer:

$175\ in^{2}$

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z----> the scale factor

x----> volume of the larger solid

y----> volume of the smaller solid

$z^{3}=\frac{x}{y}$

we have

$x=125\ in^{3}$

$y=27\ in^{3}$

substitute

$z^{3}=\frac{125}{27}$

$z=\frac{5}{3}$

step 2

Find the surface area of the larger solid

we know that

If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared

Let

z----> the scale factor

x----> surface area of the larger solid

y----> surface area of the smaller solid

$z^{2}=\frac{x}{y}$

we have

$z=\frac{5}{3}$

$y=63\ in^{2}$

substitute

$(\frac{5}{3})^{2}=\frac{x}{63}$

$x=\frac{25}{9}*63=175\ in^{2}$

3 0

3 years ago

The weight Wkg of a metal bar varies jointly

maria [59]

Answer:

d = $\sqrt{\frac{216W}{35L} }$

Step-by-step explanation:

Given that W varies jointly as L and d² then the equation relating them is

W = kLd² ← k is the constant of variation

To find k use the condition W = 140 when d = 4 and L = 54, thus

140 = k × 54 × 4² = 864k ( divide both sides by 864 )

$\frac{140}{864}$ = k , that is

k = $\frac{35}{216}$

W = $\frac{35}{216}$ Ld² ← equation of variation

Multiply both sides by 216

216W = 35Ld² ( divide both sides by 35L )

$\frac{216W}{35L}$ = d² ( take the square root of both sides )

d = $\sqrt{\frac{216W}{35L} }$

6 0

3 years ago

to communication companies offer calling plans with company X it cost $0.35 to connect and then $0.05 for each minute with compa

Mama L [17]

Answer:

X Company charges $(0.2+0.01n)\times 10^2 \ cents$ more than Company Y

Step-by-step explanation:

Given:

Cost of X company = $\$ 0.35+(\$0.05\times 1 \ minute)$

Cost of Y Company = $\$ 0.15+(\$0.04\times 1 \ minute)$

for n minutes

Cost of X company for n minutes = $\$ 0.35+(\$0.05\times n \ minute)$

Cost of Y Company for n minutes = $\$ 0.15+(\$0.04\times n \ minute)$

Difference for n minutes we get by Subtracting Cost of Y Company for n minutes by Cost of X company for n minutes

Difference for n minutes = $(\$ 0.2+\$ 0.01n)$ = $(0.2+0.01n)\times 10^2 \ cents$

X Company charges $(0.2+0.01n)\times 10^2 \ cents$ more than Company Y

6 0

3 years ago