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Vikki [24]
3 years ago
12

What does it mean if your inference is valid

Mathematics
2 answers:
maw [93]3 years ago
4 0

In logic, an inference is a process of deriving logical conclusions from premises known or assumed to be true. The term derives from the Latin term, which means "bring in." An inference is said to be valid if it's based upon sound evidence and the conclusion follows logically from the premises.

hope this helped <3

erastova [34]3 years ago
3 0
It’s logic, Hope it helps out good luck
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Dale keeps all of his pairs of shoes in his closet. select the number of shoes that deal could have in his closet. Mark all that
bekas [8.4K]
As it says he keeps 'pairs' of shoes so the answer has to be an even 'number' - ie B, C and E are all possible answers.
6 0
3 years ago
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Suppose the speeds of vehicles traveling on a highway are normally distributed and have a known population standard deviation of
erik [133]

Answer:

2.88

Step-by-step explanation:

Data provided in the question

\sigma = Population standard deviation = 7 miles per hour

Random sample = n = 32 vehicles

Sample mean = \bar X = 64 miles per hour

98% confidence level

Now based on the above information, the alpha is

= 1 - confidence level

= 1 - 0.98

= 0.02

For \alpha_1_2 = 0.01

Z \alpha_1_2 = 2.326

Now the margin of error is

= Z \alpha_1_2 \times \frac{\sigma}{\sqrt{n}}

= 2.326 \times \frac{7}{\sqrt{32}}

= 2.88

hence, the margin of error is 2.88

5 0
3 years ago
out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i
Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that P(A \cup B) = 0.95

80% passed in mathematics 75% passed in english

This means that P(A) = 0.8, P(B) = 0.75

Proportion who passed in both:

P(A \cap B) = P(A) + P(B) - P(A \cup B)

Considering the values we have for this problem

P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

0.6t = 3000

t = \frac{3000}{0.6}

t = 5000

5000 students appeared in the examination.

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3 years ago
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3 years ago
The number .0100100010001.... can be classified as
dusya [7]
1.00100010001 x 10^-2
8 0
4 years ago
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