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Vesna [10]
3 years ago
8

Solve the equation 5x^2 = -80

Mathematics
1 answer:
vodomira [7]3 years ago
3 0

Answer:

x = 4 but i dont know how to get -16

Step-by-step explanation:

divide -80 by 5 to get -16

so 4^2 = 16

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Maslowich

Answer

x  =  − 17 /10  +  I/ 10

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MATH QUESTION!! PLEASE HELP
svlad2 [7]

bro i literally had the same question about this

you in honors or something? sry i only got A

I might have B later on or something

Answer:

A.

41.125π ≈ 129

149.875π ≈ 471

Step-by-step explanation:

Surface area of smaller ganza:

3.5/2 = 1.75 x 1.75 = 3.0625 x 3.14 = 9.61625 x 2 = 19.2325

1.75 x 10 = 17.5 x 3.14 = 54.95 x 2 = 109.9 + 19.2 = 129 (Rounded)

Surface area of larger ganza:

5.5/2=2.75 x 2.75 = 7.5625 x 3.14 = 23.74625 x 2 = 47.4925

2.75 x 24.5 = 67.375 x 3.14 = 211.5575 x 2 = 423.115 + 47.4925 = 471 (Rounded)

π

129/3.14 = 41.125

471/3.14 = 149.875

4 0
2 years ago
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What is the additive inverse of the complex number 9 â€"" 4i? â€""9 â€"" 4i â€""9 4i 9 â€"" 4i 9 4i.
hram777 [196]

Additive inverse is the number you add to a given number to make the sum zero. The addition of both the number must be zero to make both numbers additive inverse.. The additive inverse of the given complex number is

-9+4i

<h3>Addictive Inverse</h3>

Addictive Inverse-Additive inverse is the number you add to a given number to make the sum zero. The addition of both the number must be zero to make both numbers additive inverse.

Let an example, if we take the number 10 and add -10 to it. Thus -10 is the additive inverse of the number 10.

Here, the given number is a complex number. A complex number is a number of the form a + bi, where a and b are real numbers. The given function is,

9-4i

The additive inverse of the above number is,-9+4i

Add both and check by equating with zero,

9-4i+(-9i+4)=0

9-4i+-9i+4=0

0=0

Hence, the additive inverse of the given complex number is -9+4i.

For more about the additive inverse, follow the link below-brainly.com/question/13715269

5 0
2 years ago
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Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

7 0
3 years ago
Questions What is the first step to solve 3x+5=17? What is the second step to solve 3x+5=171 Solve 3x+5=1 ​
Ivenika [448]

Answer:

x=4

Step-by-step explanation:

3x+5=17

17-5=12

3x=12

x=4

Hope this helps!

-AxekickNebulite

7 0
3 years ago
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