Multiply both sides by -4/7
The sum in sigma notation for the sequence will be as follows:
From
<span>5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50
first term=5
common difference=5
number of terms=10
n=nth term
thus the sum will be:
(i=2 to 10)</span>∑(5(n-1)+5)
Yo bro bro I’m bout to get my food now
It would be 8. To solve, look at it like this: 8-b=(-2). I would then look at a number line or create one if your not to sure of yourself. 8-8=0, and then 0-2=-2. 2+8=10 (the numbers you subtracted). So the answer is 10.
Answer:
16 days
Step-by-step explanation:
Given that:
Number of paramecium Aurelia doubles every 1.25days
5 days ago ; number of paramecium Aurelia = 1
How many are there now?
Using the relation :
Multiplier^(total number of days / time it takes to multiply)
Multiplier = doubles = 2
Total number rof days =. 5
Time it takes to. Multiply = 1.25
The formula becomes :
Number(n) of ptotozoan in 5days is given by 2^(5/1.25)
n = 2^(5/1.25)
n = 2^4
n = 2 * 2 * 2 * 2 =. 16
