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icang [17]
3 years ago
8

An atom that undergoes radioactive decay and has a large nucleus most likely has

Chemistry
2 answers:
Fantom [35]3 years ago
5 0
An electron number higher than the proton number I think
steposvetlana [31]3 years ago
5 0
<h2><u><em>C </em></u><em> is the answer  broskies </em></h2>
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Nina [5.8K]
I think it might be 2 but I could be mistaken sorry if I am
7 0
3 years ago
Which statement below correctly describes what changes when moving downwards from fluorine to chlorine on the periodic table?
BlackZzzverrR [31]
D to do it for a while but it was
6 0
3 years ago
Solubility
Inga [223]

Non electrolytes are Pentacarbon decahydride, Phosphorus pentachloride, Glucose.

<u>Explanation:</u>

Non electrolytes do not exist as ions in aqueous solution. Since it does not get dissociated into ions, these non electrolytes do not conduct electricity when it is dissolved or it is heated or melted.

Pentacarbon decahydride is a non electrolyte.

Magnesium chloride is an electrolyte.

Copper phosphate is an electrolyte

Sulfur trioxide is an electrolyte.

Aluminum oxide is an electrolyte

Phosphorus pentachloride do not get dissociated into its ions so it is a non-electrolyte.

Glucose gets dissolved in water but do not dissociate into ions, so it is a non electrolyte.

5 0
4 years ago
Calculate the pH of a buffer solution made by adding 15.0 g anhydrous sodium acetate (NaC2H3O2) to 100.0 mL of 0.200 M acetic ac
DiKsa [7]

Answer:

pH of Buffer Solution 5.69

Explanation:

Mole of anhydrous sodium acetate = \frac{Given mass}{Molecular mass}

                                                           = \frac{15}{82}

                                                           = 0.18 mole

 100 ml of 0.2 molar acetic acid  means

= M x V

= 0.2 x 100

= 20 mmol

= 0.02 mole

Using Henderson equation to find pH of Buffer solution

pH = pKa + log\frac{[Salt]}{[Acid]}

     = 4.74 + log\frac{0.18}{0.02}

     = 4.74 + log 9

     = 5.69

So pH of the Buffer solution = 5.69

8 0
3 years ago
Find the pH of <br> 2.1 x 10-3 [HCI]
erik [133]

Answer: pH = 2.68

Explanation: pH = - log[H3O^+] .

 HCl reacts with water : HCl + H2O ->  Cl^- + H3O^+

So [H3O^+] = c(HCl) = 0.0021 M

pH = - log(0.0021) = 2.68

 

7 0
3 years ago
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