Answer:
pH = 11.60
Explanation:
When we add a base, we are increasing [OH⁻], so the pH will be totally basic.
pH of water = 7
Basic pH > 7
We are adding 2 M . 1 mL = 2 mmoles
2 mmoles of OH⁻ are contained in 501 mL of total volume.
[OH⁻] = 2 mmol / 501 mL = 3.99×10⁻³ M
- log 3.99×10⁻³ M = 2.39 → pOH
pH = 14 - pOH → 11.61
Water equilibrium
2H₂O ⇄ H₃O⁺ + OH⁻ Kw = 1×10⁻¹⁴
NaOH → Na⁺ + OH⁻
This is a chemical reaction because a precipitate (solid) was formed from 2 liquids, and there was a color change as well
Answer:
1.750 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = ? M
V₁ = 7.14 mL
M₂ = 0.250 M
V₂ = 50 mL
Using the above formula , the molarity of acid , can be calculated as ,
M₁V₁ = M₂V₂
M₁ * 7.14 mL = 0.250 M * 50mL
M₁ = 1.750 M
Hence, the molarity of the hydrochloric acid = 1.750 M
Answer:
n = 0.01302 moles
Explanation:
Pressure = 1.3 atm
Temperature = 31 °C + 273 = 304 K ( Converting to kelvin temperature)
Number of moles = ?
Volume = 250 mL = 0.250 L
These quantities are related by the equation below;
PV = nRT
n = PV / RT
n = (1.3 * 0.250) / (0.0821 * 304)
n = 0.01302 moles
