-130KJ is the standard heat of formation of CuO.
Explanation:
The standard heat of formation or enthalpy change can be calculated by using the formula:
standard heat of formation of reaction = standard enthalpy of formation of product - sum of enthalpy of product formation
Data given:
Cu2O(s) ---> CuO(s) + Cu(s) ∆H° = 11.3 kJ
2 Cu2O(s) + O2(g) ---> 4 CuO(s) ∆H° = -287.9 kJ
CuO + Cu ⇒ Cu2O (-11.3 KJ) ( Formation of Cu2O)
When 1 mole Cu20 undergoes combustion 1/2 moles of oxygen is consumed.
Cu20 + 1/2 02 ⇒ 2CuO (I/2 of 238.7 KJ) or 119.35 KJ
So standard heat of formation of formation of Cu0 as:
Cu + 1/2 02 ⇒ CuO
putting the values in the equation
ΔHf = ΔH1 + ΔH2 (ΔH1 + ΔH2 enthalapy of reactants)
heat of formation = -11.3 + (-119.35)
= - 130.65kJ
-130.65 KJ is the heat of formation of CuO in the given reaction.
The substance that can act as an Arrhenius base in aqueous solution is sodium hydroxide since NaOH dissociates in water giving the sodium ions and the hydroxide ions. An Arrhenius base is a substance that is characterized by forming hydroxide ions in an aqueous solution.
Oil-based food coloring used to make the letters, won't dissolve in water. According to some sources, oil-based food coloring is either insoluble or immiscible in water. Because it is present in more solutions, water serves as the universal solvent.
<h3>
Universal solvent:-</h3>
A substance that displaces most compounds is known as a universal solvent. Because it dissolves more chemicals than any other solvent, water is known as the universal solvent.
<h3>
What chemicals lack solvability?</h3>
Sand, plastic, wood, metal, glass, and cloth are examples of insoluble materials. At standard conditions of pressure and temperature, these compounds never dissolve in water or any other solvent. Other examples of insoluble materials are sugars and inorganic salts.
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The compound given (i.e. 3,3-dimethyl-1-butanol) is primary alcohol (1°) because the functional group (-OH) shows that it is alcohol is attached to a primary carbon (i.e terminal carbon).
The oxidation of all primary alcohols results in the formation of aliphatic aldehyde(also known as alkanal).
Suppose, it is secondary alcohol;
The oxidation of secondary alcohol results in the formation of ketone(also known as alkanone).
When 3,3-dimethyl-1-butanol undergoes oxidation, the suffix "ol" in the alcohol changes to "al"
Therefore, 3,3-dimethyl-1-butanol changes to 3,3-dimethyl-1-butanal after undergoing oxidation.
In conclusion, the product when 3,3-dimethyl-1-butanol undergoes oxidation is: 3,3-dimethylbutanal.
As such, option 2 is correct.
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The gas is disposed proportional to the temperature to pressure of the particles
