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icang [17]
3 years ago
9

HELP ME WILL MARK YOU AS BRAINLIEST IF CORRECT

Mathematics
1 answer:
Verdich [7]3 years ago
6 0

Answer:

C. (-3, 2, -1)

Step-by-step explanation:

There are two types of matrices. One is REF and the other is what makes REF simpler--RREF. We use RREF to solve for REF because it makes the solution easy to find. RREF is displayed in your problem... it means that it's already solved, so the answers are already given on the right side, which is -3,2,-1. This only works with the combination provided (with the 0s and 1s). Otherwise, you'd have to solve.

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Log7 (-5k-3)=log7 -4k
exis [7]

Answer:

k = -3

Step-by-step explanation:

log7(-5k - 3) = log7 (-4k)

---> -5k - 3 = -4k

-k - 3 = 0

k = -3

5 0
3 years ago
Plz help me well mark brainliest if correct......?
Maru [420]

Answer:

It think it is A brainliest?

Step-by-step explanation:

4 0
3 years ago
Brainiest fastest answer no link or bot or I report you I report you if you report me
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I did this really quick so I hope all the answers are right, and double check them if you have time just in case

4 0
3 years ago
Write each percent as a fraction and as a decimal to the nearest hundredth.
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8 0
3 years ago
If f(x) =-2+8 and g(x) = square root of x+9 which statement is true
lidiya [134]

The statement that -6 is in the domain of f(g(x)) is true

<h3>Complete question</h3>

If f(x) = -2x + 8 and g(x) = \sqrt{x + 9, which statement is true?

  • -6 is in the domain of f(g(x))
  • -6 is not in the domain of f(g(x))

<h3>How to determine the true statement?</h3>

We have:

f(x) = -2x + 8

g(x) = \sqrt{x + 9

Start by calculating the function f(g(x)) using:

f(g(x)) = -2g(x) + 8

Substitute g(x) = \sqrt{x + 9

f(g(x)) = -2\sqrt{x + 9} + 8

Set the radicand to at least 0

x + 9 \ge 0

Subtract 9 from both sides

x \ge -9

This means that the domain of f(g(x)) are real numbers greater than or equal to -9. i.e. -9, -8, -7, -6, ...........

Hence, the statement that -6 is in the domain of f(g(x)) is true

Read more about domain at:

brainly.com/question/24539784

#SPJ1

3 0
2 years ago
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