Answer:
a. 24
b. 12
Step-by-step explanation:
a. You can choose from 4 cities for the first performance, then from 3 cities, then from 2 cities, then the last city.
4 * 3 * 2 * 1 = 24
b. Think of the three performances in California as a unit. Within this unit, you can choose from 3 cities for the first one, then 2 cities for the second one, and finally 1 city for the last one.
3 * 2 * 1 = 6
Now you can have the 3 California performances first, followed by Denver, or Denver first followed by California.
6 * 2 = 12
<u>Answer:</u>
19.15
<u>Step-by-step explanation:</u>
16.80 x 5% = 0.84
16.80 - 0.84 = 15.96
15.96 x 20% = 3.19
15.96 + 3.19 = 19.15
We define the probability of a particular event occurring as:

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.
Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:
(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5
So, we have

probability of rolling at least one 5.
Answer:
.70(x)+1.15(25)=48
Step-by-step explanation: