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alexgriva [62]
2 years ago
8

During Sonia's trip across the country, she traveled 2,884 miles. Her trip took 7 days. Find the unit rate to represent the aver

age miles she traveled per day during the trip.
Mathematics
1 answer:
S_A_V [24]2 years ago
3 0
\frac{2,884}{7}=\\412

412 miles.
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A vehicle is purchased for $18,000, with a down payment of $6,098. The balance in financed for three years at an annual rate of
mestny [16]
The Present value of an annuity is given by PV = P(1 - (1 + r/t)^-nt)/(r/t)
where: P is the monthly payment, r is the annual rate = 7% = 0.07, t is the number of periods in one year = 12 and n is the number of years = 3.

18,000 - 6,098 = P(1 - (1 + 0.07/12)^-(3 x 12)) / (0.07/12)
11,902 = P(1 - (1 + 0.07/12)^-36) / (0.07/12)
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Therefore, monthly payment = $367.50
7 0
2 years ago
A professional bowler wanted to gather data about the cost of local bowling leagues in the area. After collecting and plotting t
Yuliya22 [10]

The slope in this scenario is 12 and , starting at $30 the cost will increase by $12 per month .

In the question ,

it is given that

the average bowling league has  one time registration fees

and

a monthly fees .

let the number of months the training continues be "x" .

the equation is given as y = 12x + 30

since the one time registration fees is fixed so , it will be 30 .

and the monthly fees varies with the number of months of training , so monthly fees will be 12x  .

On comparing the given equation y = 12x + 30 with slope intercept form of the line y = mx + c  ,
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slope (m) = 12 .

and starting cost = $30 and the increase in cost by $12 per month .

Therefore , The slope in this scenario is 12 and , starting at $30 the cost will increase by $12 per month , the correct option is (c) .

The given question is incomplete , the complete question is

A professional bowler wanted to gather data about the cost of local bowling leagues in the area. After collecting and plotting the data, it was determined that the average bowling league consists of a one-time registration fee and a monthly fee modeled by the equation y = 12x + 30.

Identify and interpret the slope in this scenario.

(a) The slope is 30. Starting at $12, the cost will increase by $30 per month.

(b) The slope is 30. Starting at $12, the cost will decrease by $30 per month.

(c) The slope is 12. Starting at $30, the cost will increase by $12 per month.

(d) The slope is 12. Starting at $30, the cost will decrease by $12 per month.

Learn more about Slope here

brainly.com/question/24436844

#SPJ1

4 0
1 year ago
A particle sits on a smooth surface and is acted upon by a time dependent horizontal force, giving it an
garik1379 [7]

(a) By the fundamental theorem of calculus,

<em>v(t)</em> = <em>v(0)</em> + ∫₀ᵗ <em>a(u)</em> d<em>u</em>

The particle starts at rest, so <em>v(0)</em> = 0. Computing the integral gives

<em>v(t)</em> = [2/3 <em>u</em> ³ + 2<em>u</em> ²]₀ᵗ = 2/3 <em>t</em> ³ + 2<em>t</em> ²

(b) Use the FTC again, but this time you want the distance, which means you need to integrate the <u>speed</u> of the particle, i.e. the absolute value of <em>v(t)</em>. Fortunately, for <em>t</em> ≥ 0, we have <em>v(t)</em> ≥ 0 and |<em>v(t)</em> | = <em>v(t)</em>, so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of

∫₀⁸ <em>v(u)</em> d<em>u</em> = ∫₀⁸ (2/3 <em>u</em> ³ + 2<em>u</em> ²) d<em>u</em> = [1/6 <em>u</em> ⁴ + 2/3 <em>u</em> ³]₀⁸ = 1024

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Find the inverse of the function.<br> f-^1(x)= (x – 5)^3 + 1
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Answer:

Step-by-step explanation:

To find the inverse of function y=f(x), swap variables and then solve for the original variable.

y=(x-5)^3+1\\ \\ x=(y-5)^3+1\\ \\ x-1=(y-5)^3\\ \\ \sqrt[3]{x-1}=y-5\\ \\ y=\sqrt[3]{x-1}+5\\ \\ f^{-1}(x)=\sqrt[3]{x-1}+5

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Gelneren [198K]

Unfortunately, there is no way I can find the value of X and Y because there is no question for it.

You can either find the value of X and Y in the problem or make X and Y your own value if you need to find something that is equivalent.

I hope this helped.

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3 years ago
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