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Tanya [424]
3 years ago
11

Which of the following is a rational number?

Mathematics
1 answer:
densk [106]3 years ago
3 0
An irrational number is a number that cannot be expressed as a fraction, like Pi
-------------------------------
The square root of 2 is irrational as it cannot be expressed as a fraction since the decimal never stops and never repeats.
Same goes for the square root of 3, and 5
-------------------------------
Square root of 1 is rational as because the square root of 1 is 1, and the number 1 can be expressed as a fraction (1/1)
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Write a polynomial expression, in simplified form, that represents the AREA of the blanket and use the expression to evaluate th
pochemuha

Answer:

Polynomial expression that represents the area of blanket:

A(x)=(6x^2+5x-21)cm^2

If x=2: A(2)=13cm^2  

Step-by-step explanation:

The area of the rectangle can be calculated with the formula:

A=lw

Being l the lenght of the rectangle and w the width of the rectangle.

In this case, the lenght and the width are represented with:

l=(3x+7)cm

w=(2x-3)cm

Substitute them into  A=lw:

 A(x)=(3x+7)(2x-3)

Then:

Use Distributive property (Remember the Product of powers property: b^a*b^c=b^{(a+c)} ):

A(x)=(3x+7)(2x-3)\\A(x)=6x^2-9x+14x-21

Add like terms:

A(x)=(6x^2+5x-21)cm^2 (Simplied form)

Evaluate x=2:

A(2)=(6(2)^2+5(2)-21)cm^2\\A(2)=(6(4)+10-21)cm^2\\A(2)=(24-11)cm^2\\A(2)=13cm^2

6 0
3 years ago
Can Someone please help me with this answer? I'm not good at fractions.
Rina8888 [55]

Answer: 283/20

Step-by-step explanation:

first u can change them into improper fractions. Then take the LCM of the denominators which will make the denominators same. Its easy after that.

7 0
3 years ago
What is the answer to 8ab-2b+ab-b
lora16 [44]
8ab-2b+ab-b
8ab+ ab= 9ab
-2b-b= -3b

Answer: 9ab - 3b
4 0
4 years ago
Read 2 more answers
The amount, y, a museum spends on new
vladimir2022 [97]

Answer:

x = 7/0.25

x =$28

Step-by-step explanation:

y=0.25x

but y= $7(amount spent)

put 7

6 0
3 years ago
Give an example of a nested sequence of open bounded intervals such that there is no point that belongs to all of the intervals
Damm [24]


let n take values 1,2,3... infinity

then the sequence is:


(0,1/n)

for every number greater than zero there exist such n that (0,1/n) does not contain that number.
5 0
4 years ago
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