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3 years ago

The circumference of a circle is

Mathematics

1 answer:

EleoNora [17]3 years ago

8 0

Answer:

C=2πr

Step-by-step explanation:

The circumference is the total distance around the circle.

C=πd but d = 2r.

:.C=2πr.

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Does 6n-18=4(n+2) equal 1n?

Mariulka [41]

Answer:

No.

Step-by-step explanation:

If we were to fill in the slots, the equation would be...

6x3-18=4

6 times three is 18, and 18 - 18 equals 0. So the answer would not be 1.

4 0

3 years ago

Event A has a 0.3 probability of occuring and event B has a 0.4 probability of occuring. A and B are independent events. What is

GarryVolchara [31]

When you say either, you add both A and B
0.3+0.4=0.7
Your answer is 0.70 which means 70%

4 0

3 years ago

Read 2 more answers

What is the decimal for 4 2/3?

muminat

4.67 would be a rounded answer. Really it's 4.666666666666666666 (the 6 go on forever) but we can't write that out.

8 0

3 years ago

Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx = 1$

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have

$\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx = 1$

Since c is a constant, we can bring it out of the integral sign; to give us

$c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx = 1$

Open the bracket

$c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx = 1$

Integrate with respect to y

$c\int\limits^3_0 {\frac{xy^{2}}{2} +\frac{xy^{3}}{3} } \, dx (0,3}) = 1$

Substitute 0 and 3 for y

$c\int\limits^3_0 {(\frac{x* 3^{2}}{2} +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2} +\frac{x * 0^{3}}{3})} \, dx = 1$

$c\int\limits^3_0 {(\frac{x* 9}{2} +\frac{x * 27}{3} ) - (0 +0) \, dx = 1$

$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

$\frac{c}{6}\int\limits^3_0 (81x ) \, dx = 1$

Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

$\frac{c}{6} * \frac{81 * 3^{2} - 81 * 0^{2}}{2} = 1$

$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

$\frac{729c}{12} = 1$

Multiply both sides by $\frac{12}{729}$

$c = \frac{12}{729}$

$c = 0.0165 (Approximately)$

8 0

3 years ago

First one to answer get the Brainiest<br> help plz

Deffense [45]

Answer:

D. The ratio of the circumference to the diameter is the same for both sides

Step-by-step explanation:

dilation in a shape is either it becoming bigger or smaller, no matter what factor you dilate the shape by its ratio will still remain the same, such as when you simplify a fraction.

6 0

3 years ago