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Tomtit [17]
3 years ago
14

2. Simplify 2(54−1)3 completely. Show as much work as possible for full credit.

Mathematics
2 answers:
poizon [28]3 years ago
7 0

(2 \times 54 - 2)3 = 108 - 2 \times 3 = 106 \times 3 = 318

Rom4ik [11]3 years ago
6 0

Answer:

\boxed{\bold{318}}

Step By Step Explanation:

Calculate Within Parenthesis: \bold{(54-1)}

\bold{53}

Rewrite Equation

\bold{2\cdot \:53\cdot \:3}

Multiply: \bold{2\cdot \:53\cdot \:3}

\bold{318}

➤ \boxed{\bold{Mordancy}}

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3 years ago
Which property of multiplication is shown? 6 · 1 = 1 · 6
saw5 [17]

Answer: Commutative property of multiplication  

Step-by-step explanation: The problem 6 · 1 = 1 · 6 demonstrates the commutative property of multiplication.

In other words, the commutative property of multiplication says that changing the order of the factors does not change the product.  

So for example here, 6 · 1 is equal to 6 and 1 · 6 also equals 6.

Since 6 = 6, we can easily see that 6 · 1 must be equal to 1 · 6.

In more general terms, the commutative property of multiplication can be written as a · b = b · a where <em>a</em> and <em>b</em> are variables that can represent any numbers.

5 0
3 years ago
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Which is the value of x is in the domain of f(x)=x-8
mrs_skeptik [129]

Answer:

8

Step-by-step explanation:

Solve for x:

x - 8 = 0

Hint: | Isolate terms with x to the left hand side.

Add 8 to both sides:

x + (8 - 8) = 8

Hint: | Look for the difference of two identical terms.

8 - 8 = 0:

Answer: x = 8

8 0
3 years ago
While grading her students' most recent quiz on equation solving, Mrs. Jones calculated that approximately forty percent of her
EastWind [94]

The given equation is,

3(-n+4)+5n=2n

Part 1:

Solve the above equation for n.

Using distributive property of multiplication,

\begin{gathered} -3n+3\times4+5n=2n \\ -3n+12+5n=2n \end{gathered}

Now, group the like terms.

-3n+5n-2n+12=0

Now, add the like terms.

\begin{gathered} -5n+5n+12=0 \\ 0=-12 \end{gathered}

0=-12 is a false statement.

Since we obtained a false statement, the given equation has no solution.

So, option b is correct.

Part 2:

The option (a) is n=3.

If while solving an equation, a single value is obtained for the variable, then the equation has only a single solution. If n=3 is obtained after solving the equation, then the student should chose option (a) as the answer.

The option (b) is "no solution".

While solving an equation, if we obtain an equation which is mathematically false, then the equation will have no solution. So, no solution is chosen when no value is obtained for n and the final equation is mathematically false.

The option (c) is "infinitely many solutions".

While solving an equation, if we obtain an equation which is mathematically correct such as 0=0, 7=7 etc., then the equation will have infinietly many solutions. So, infinitely many solutions is chosen when no value is obtained for n and the final equation is mathematically correct.

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1 year ago
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Amiraneli [1.4K]

Answer:

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Step-by-step explanation:

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