Please help me with this, I will give brainliest.

Which of the following equations is in standard form?

swat32

D. 2x+3y=14 is the correct answer.

6 0

3 years ago

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How many swimmers are holding exaclty 3 toy whales?

Setler79 [48]

About 40 swimmers maybe more

6 0

3 years ago

Suppose that the functions s and t are defined for all real numbers x as follows.

PolarNik [594]

Answer:

(s-t)(-1) = -1

(s+t)(-1) = -7

Step-by-step explanation:

Given the following set of functions

s(x)=2x-2

t(x)=3x

(s-t)(x) = s(t) - t(x)

(s-t)(x) = 2x - 2 - 3x

(s-t)(x) = -x -2

(s-t)(-1) = -(-1) - 2

(s-t)(-1) = 1-2

(s-t)(-1) = -1

(s+t)(x) = s(t) + t(x)

(s+t)(x) = 2x - 2 + 3x

(s+t)(x) = 5x -2

(s+t)(-1) = 5(-1) - 2

(s+t)(-1) = -5-2

(s+t)(-1) = -7

8 0

3 years ago

A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal

GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean income = $\frac{\sum X}{n}$ = $4.70

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = $1.83

n = sample of parking meters = 10

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.262 < $t_9$ < 2.262) = 0.95 {As the critical value of t at 9 degrees of

freedom are -2.262 & 2.262 with P = 2.5%}

P(-2.262 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.262) = 0.95

P( $-2.262 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu$ < $2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $4.70-2.262 \times {\frac{1.83}{\sqrt{10} } }$ , $4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } }$ ]

= [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error = $2.262 \times {\frac{s}{\sqrt{n} } }$

= $2.262 \times {\frac{1.83}{\sqrt{10} } }$ = 1.31

4 0

3 years ago

Given the quadratic function f(x) = 2x + 5x-12, what is the value of f(-2)?

tino4ka555 [31]

Answer:

-26

Step-by-step explanation:

first substitute -2 for x : 2(-2)+5(-2)-12

-4+-10-12

-14-12

-26

-26 is your answer

pls mark me brainliest if this helps !

6 0

3 years ago

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