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3 years ago

This size of battery is found in a Hybrid Electric Vehicle (HEV).

Engineering

2 answers:

atroni [7]3 years ago

7 0

Answer:

In hybrid electric vehicles normally 40 kWh battery is used which is nearly of 150 kg

Explanation:

A family car which is middle in size neither very large nor very small need a battery if capacity of 32 kWh to 40 kWh

And the size of the battery is dependent in the capacity of the battery, the battery which has large capacity has larger size and the battery with less capacity are also smaller in size

And the battery which has a capacity of 40 kWh is normally of 1.5 tons , that is 150 kg

Vlad1618 [11]3 years ago

4 0

The subcompact EV comes with a battery that has 12–18kWh, the mid-sized family sedan has a 22–32kWh pack, and the luxury models by Tesla stand alone with an oversized battery boasting 60–100kWh to provide extended driving range and achieve high performance.

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How meny people live in new york

nydimaria [60]

Answer:

8.419 million (2019) at 2019

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3 years ago

The sports car has a weight of 4900 lblb and center of gravity at GG. If it starts from rest it causes the rear wheels to slip a

Zinaida [17]

Answer:

2.27secs

Explanation:

The car will take 2.27secs to reach a speed of 10 ft/s.

Kindly go through the attached files for a step by step solution that will show you how the answer was gotten and the normal reaction of both the front and rear wheels.

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3 years ago

A piston–cylinder assembly contains 5 kg of air, initially at 2.0 bar, 30 C. The air undergoes a process to a state where the pr

Ainat [17]

Answer: wor done is 145. 06kJ

Heat transfer is 135.53kJ

Explanation:

No of moles of air = mass/molar mass = 5000g/28gmol^-1 = 172.65mol

P1 = 2bar =2*101300 =202600pa

T1 = 30° +273k = 303k

P2 =p1 = 202600pa

V2 =? T2 =?

Using pV = nRT

R = 8.314 PA m^3 mol^-1 k^-1

V1 = (172.65*8.314*303)/202600

V1 = 2.146m^3

For second state, 1.5pv = const = P1V1

V2 = (202600*2.146)/(1.5*202600)

V2 = 1.43m^3

Volume change = 2.146 - 1.43 =0.715m^3

Word done = pressure* volume change

W = 202600*0.716 = 145061.6J

= 145.061kJ

Using V1/T1 = V2/T2

T2 = V2T1/V1

=(1.43*303)/2.146 = 201.9k

For internal energy U

U = nCv*(T2 - T1)

*CV is the heat capacity at const. vol approximately 0.718J mol^-1 k^-1

U = 172.65*0.718*(201.9-303)

U = -12532.6J = -12.532kJ

The -ve means the system lost internal energy.

Q = U+W = total heat energy of system

Q = - 12.532+145.061 = 132.52 kJ

7 0

4 years ago

The vertical force P acts on the bottom of the plate having a negligible weight. Determine the shortest distance d to the edge o

Greeley [361]

Answer:

The shortest distance d to the edge of the plate is 66.67 mm

Concepts and reason

Moment of a force:

Moment of a force refers to the propensity of the force to cause rotation on the body it acts upon. The magnitude of the moment can be determined from the product of force’s magnitude and the perpendicular distance to the force.

Moment(M) = Force(F)×distance(d)

Moment of inertia ( I )

It is the product of area and the square of the moment arm for a section about a reference. It is also called as second moment of inertia.

First prepare the free body diagram of sectioned plate and apply moment equilibrium condition and also obtain area and moment of inertia of rectangular cross section. Finally, calculate the shortest distance using the formula of compressive stress (σ) in combination of axial and bending stress

Solution and Explanation:

[Find the given attachments]

6 0

4 years ago

At steady state, air at 200 kPa, 325 K, and mass flow rate

Vera_Pavlovna [14]

Letra A

A letra

A.
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3 years ago