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kherson [118]
3 years ago
5

The maximum stress that a bar will withstand before failing is called • Rapture Strength • Yield Strength • Tensile Strength • B

oth 1 & 2
Engineering
1 answer:
konstantin123 [22]3 years ago
7 0

Answer: Rupture strength

Explanation: Rupture strength is the strength of a material that is bearable till the point before the breakage by the tensile strength applied on it. This term is mentioned when there is a sort of deformation in the material due to tension.So, rupture will occur before whenever there are chances of failing and the material is still able to bear stresses before failing.  

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An electric sign takes 40A from a 240V supply. What current will it take if the voltage is raised to 300V. Help PLEASE!!!​
Sergeeva-Olga [200]

.........................

3 0
3 years ago
A plate clutch is used to connect a motor shaft running at 1500rpm to shaft 1. The motor is rated at 4 hp. Using a service facto
vazorg [7]

Answer:

(M_t)_{rated}=61.11lb-in

Explanation:

speed of motor (N)=1500 rpm

power=4 hp = 4 \times 0.7457 =2.9828 KW

service factor(k)= 2.75

now,

KW=\frac{2\pi n M_t}{60 \times 10^6} \\2.9828=\frac{2\pi \times 1500 M_t}{60 \times 10^6}\\M_t=\frac{2.9828\times 60 \times 10^6}{2\pi \times 1500 }

M_t= 18,989.09 \ N-mm= 168.06 lb-in

torque rating

(M_t)_{design}=k_s\times (M_t)_{rated}\\168.06= 2.75\times (M_t)_{rated}\\(M_t)_{rated}=\frac{168.06}{2.75} \\(M_t)_{rated}=61.11lb-in

4 0
4 years ago
A circuit contains a 40 ohm resistor and a 60 ohms resistor connected in parallel. If you test this circuit with a DMM you shoul
lorasvet [3.4K]
<h2>Answer:</h2>

24Ω

<h2>Explanation:</h2>

When resistors are connected in parallel, the reciprocal of their combined resistance, when read with a DMM (Digital Multimeter - for measuring various properties of a circuit or circuit element such as resistance...) is the sum of the reciprocals of their individual resistances.

For example if two resistors of resistances R₁ and R₂ are connected together in parallel, the reciprocal of their combined resistance Rₓ is given by;

\frac{1}{R_x} = \frac{1}{R_1} + \frac{1}{R_2}

Solving for Rₓ gives;

R_{x} = \frac{R_1 * R_2}{R_1 + R_2}          ------------------(i)

From the question;

Let

R₁ = resistance of first resistor = 40Ω

R₂ =  resistance of second resistor = 60Ω

Now,

To get their combined or total resistance, Rₓ, substitute these values into equation (i) as follows;  

R_{x} = \frac{40 * 60}{40 + 60}

R_{x} = \frac{2400}{100}

R_{x} = 24 Ω

Therefore, the total resistance is 24Ω

4 0
3 years ago
An uncharged capacitor is connected to a resistor and a battery. Choose what happens to current, potential difference and charge
Ilya [14]

Answer:

  • The charge on the plates will increase with time
  • The potential difference across the capacitor starts with zero and then increases gradually to a maximum value
  • The current through the circuit starts high and then drops exponentially

Explanation:

<u>Case : An uncharged capacitor is connected to a resistor and a battery in a closed circuit.</u>

  • The charge on the plates will increase with time

applying this equation : Q = Q_{0}  [ 1 - e^{\frac{-t}{RC} } ]  as the value of (t) increases the value of Q increases i.e. charge on the plates

  • The potential difference across the capacitor starts with zero and then increases gradually to a maximum value

applying this equation : V = V_{0}  [ 1 - e^{\frac{-t}{RC} } ]

  • The current through the circuit starts high and then drops exponentially

current : I = I_{0}  e^{\frac{-t}{RC} }

6 0
3 years ago
The beam is supported by a pin at A and a roller at B which has negligible weight and a radius of 15 mm. If the coefficient of s
Anettt [7]

Answer:

33.4

Explanation:

Step 1:

\sumMo=0 (moment about the origin)

Fb(15)-Fc(15)=0

Fb=Fc

Step 2:

\sumFx=0

-Fb-Fccos\theta+Ncsin\theta=0

Fc=0.3Nc=Fb

-0.3Nc-0.3Nccos\theta+Ncsin\theta=0

(-0.3-cos\theta+sin\theta)Nc=0----(1)

\sumFy=0

Nccos\theta+Fcsin\theta-Nb=0

Nccos\theta+0.3Ncsin\theta-Nc=0

Nc[cos\theta+0.3sin\theta-1]=0--------(2)

Solving eq (1) and eq (2)

\theta=33.4

Step 3:

As the roller is a two force member

2(90-\phi)+\theta=180

\phi=\theta/2

\phi=Tan(\muN/N)-1

\phi=16.7

\theta=2x16.7=33.4

5 0
3 years ago
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